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marishachu [46]
2 years ago
15

The function y =30+5x represents the cost y (in dollars) of having your dog groomed and buying x for extra services . sorry my m

ind is numb I have had a butt ton of work cut out for me.​

Mathematics
1 answer:
Evgesh-ka [11]2 years ago
8 0

Answer:

Hello! I am also having trouble in algebra! From what I can see so far this is what the problem should look like...

Step-by-step explanation:

A. Yes, it s a linear function because it matches the equation y=mx+b

B. The domain is 1, 2, 3 , 4, and 5. This is because there are 5 services you can choose from. The domain is discrete because you can't have half a service.

C. Because I'm also doing this book (I'm in Algebra 1 in 8th grade), I'm also just learning this! So sorry, but I don't know how to solve this one either... can someone please help?

Thanks! Also, just a tip, if you're having trouble ever again go to slader.com where they have all the answers to any textbook. They also have really good explanations! However, for this one, I didn't understand it on slader so I came on here! Good luck and if anyone can help with C that would be much appreciated.

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Suppose that for a recent admissions class, an Ivy League college received 2,851 applications for early admission. Of this group
stepan [7]

Answer:

A) The probability is a measure of the likelihood than an event is going to occur. In this case we can calculate the probability of X as:

P(X) = X/N where X is the number of ways X occurs and N is the total number of events.

P(E) = E/N = 1033/2851 = 0.3623

P(R) = R/N = 854/2851 = 0.2995

P(D) = D/N = 964/2851 = 0.3381

B)

E and D are mutually exclusive because the students that were admitted early where not deffered to regular admission pool. There is no chance that there is a student that were admitted erarly and deffered at the same time, so the intersection between E and D (E∩D) is 0.

C) The number of students that were early accepted is 1033 and the total number of students accepted is 2375. The probability is going to be:

P = 1033/2375 = 0.4349

D)

In this case we can reformulate the question as: What is the probability of being accepted if you apply for early admission? This

Since 18% of the students deffered to regular admission pool 0.18 × 964 = 174 were admitted at the end.

The probability of being deffered and then accepted is going to be:

P(DA) = 174/2831 = 0.0610

The probability of ramdomly selecting a students that has been early accepted or deffered and then accepted is going to be:

P(E or DA) = 0.0610 + 0.3623 = 0.4233

This is the addition rule.

3 0
2 years ago
The picture shows two sizes of shipping boxes with measurements in inches. The boxes are rectangular prisms. There are two recta
MakcuM [25]

Answer:

6

Step-by-step explanation:

7 0
2 years ago
A contractor developed a multiplicative time-series model to forecast the number of contracts in future quarters, using quarterl
dusya [7]

There is a missing content in the question.

After the statements and before the the options given; there is an omitted content which says:

Referring to Table 16-5, in testing the coefficient of X in the regression equation (0.117) the results were a t-statistic of 9.08 and an associated p-value of 0.0000. Which of the following is the best interpretation of this result?

Answer:

C. The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05).

Step-by-step explanation:

From the given question:

The resulting regression equation can be represented as:

\hat Y = 3.37 + 0.117 X - 0.083 Q_1 + 1.28 Q_2 + 0.617Q_3

where;

the estimated number of contracts in a quarter X is the coded quarterly value with X = 0

the first quarter of 2010 Q1 is a dummy variable equal to 1 in the first quarter of a year and 0 otherwise

Q2 is a dummy variable equal to 1 in the second quarter of a year and 0 otherwise

Q3 is a dummy variable equal to 1 in the third quarter of a year and 0 otherwise

Our null and alternative hypothesis can be stated as;

Null hypothesis :

H_0 :  The quarterly growth rate in the number of contracts is not  significantly different from 0% (? = 0.05)

H_a:  The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

The decision rule is to reject the null hypothesis if the p-value is less than 0.05.

From the missing omitted part we added above; we can see that the   t-statistics value = 9.08 and the p-value = 0.000 .

Conclusion:

Thus; we reject the null hypothesis and accept the alternative hypothesis. i.e

The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

4 0
2 years ago
Which of the following are dimensionally consistent? (Choose all that apply.)(a) a=v / t+xv2 / 2(b) x=3vt(c) xa2=x2v / t4(d) x=v
Bumek [7]

Complete Question

The  complete question is shown on the first uploaded image

Answer:

A

is dimensionally consistent

B

is not dimensionally consistent

C

is dimensionally consistent

D

is not dimensionally consistent

E

is not dimensionally consistent

F

is dimensionally consistent

G

is dimensionally consistent

H

is not dimensionally consistent

Step-by-step explanation:

From the question we are told that

   The equation are

                        A) \   \  a^3  =  \frac{x^2 v}{t^5}

                       

                       B) \   \  x  =  t

 

                       C \ \ \ v  =  \frac{x^2}{at^3}

 

                      D \ \ \ xa^2 = \frac{x^2v}{t^4}

                      E \ \ \ x  = vt+ \frac{vt^2}{2}

                     F \ \ \  x = 3vt

 

                    G \ \ \  v =  5at

 

                    H \ \ \  a  =  \frac{v}{t} + \frac{xv^2}{2}

Generally in dimension

     x - length is represented as  L

     t -  time is represented as T

     m = mass is represented as M

Considering A

           a^3  =  (\frac{L}{T^2} )^3 =  L^3\cdot T^{-6}

and    \frac{x^2v}{t^5 } =  \frac{L^2 L T^{-1}}{T^5}  =  L^3 \cdot T^{-6}

Hence

           a^3  =  \frac{x^2 v}{t^5} is dimensionally consistent

Considering B

            x =  L

and      

            t = T

Hence

      x  =  t  is not dimensionally consistent

Considering C

     v  =  LT^{-1}

and  

    \frac{x^2 }{at^3} =  \frac{L^2}{LT^{-2} T^{3}}  =  LT^{-1}

Hence

   v  =  \frac{x^2}{at^3}  is dimensionally consistent

Considering D

    xa^2  = L(LT^{-2})^2 =  L^3T^{-4}

and

     \frac{x^2v}{t^4}  = \frac{L^2(LT^{-1})}{ T^5} =  L^3 T^{-5}

Hence

    xa^2 = \frac{x^2v}{t^4}  is not dimensionally consistent

Considering E

   x =  L

;

   vt  =  LT^{-1} T =  L

and  

    \frac{vt^2}{2}  =  LT^{-1}T^{2} =  LT

Hence

   E \ \ \ x  = vt+ \frac{vt^2}{2}   is not dimensionally consistent

Considering F

     x =  L

and

    3vt = LT^{-1}T =  L      Note in dimensional analysis numbers are

                                                       not considered

  Hence

       F \ \ \  x = 3vt  is dimensionally consistent

Considering G

    v  =  LT^{-1}

and

    at =  LT^{-2}T =  LT^{-1}

Hence

      G \ \ \  v =  5at   is dimensionally consistent

Considering H

     a =  LT^{-2}

,

       \frac{v}{t}  =  \frac{LT^{-1}}{T}  =  LT^{-2}

and

    \frac{xv^2}{2} =  L(LT^{-1})^2 =  L^3T^{-2}

Hence

    H \ \ \  a  =  \frac{v}{t} + \frac{xv^2}{2}  is not dimensionally consistent

8 0
2 years ago
If it takes 10 seconds for 10 printers to print out 10 pages of paper, how many seconds will it take 50 printers to print out 50
Fed [463]

Lets use the formula RWT=J to solve this, where,

  • R is the rate
  • W is the number of workers/things
  • T is time
  • J is number of jobs/things

<em><u>"If it takes 10 seconds for 10 printers to print out 10 pages of paper"</u></em> - here -

W is 10 printers, T is 10 seconds,  and J is 10 pages. We can write:

R(10)(10)=10\\R(100)=10\\R=\frac{10}{100}\\R=0.1


<u><em>"how many seconds will it take 50 printers to print out 50 pages of paper"</em></u><em> - here we use R=0.1 (previously found) to figure out T.</em>

<em>RWT=J\\(0.1)(50)T=50\\5T=50\\T=\frac{50}{5}\\T=10</em>

So it will take 10 seconds for 50 printers to print 50 pages.


ANSWER: 10 seconds

4 0
2 years ago
Read 2 more answers
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