Answer:
the new Zealand international was the first time he had scored in a day and a half century for any of his
The answer is A as he has all of the quarters when he spends no time in the arcade
All transportation (bus, cab, train) are all similarly likely to be selected, and 1 of them must be selected at morning and evening, so we get: P (bus) = P (cab) = P (train) = 1/3. We also have P(no cab in evening) = P(no cab at morning) = 2/3
Now, P(using cab exactly once) = P(cab at morning and no cab in the evening) + P(no cab at morning and cab in the evening)
= P(cab, no cab) + P(no cab, cab)
= 1/3 * 2/3 + 2/3 * 1/3
= 2/9 + 2/9
= 4/9
Probability that Elizabeth uses a cab only once is 4/9.
Mean = Sum of all the observations/ Number of observations = (87+46+90+78+89)/5 = 78
Variance = SD^2 ------ SD = Standard deviation
It means that with Variance, square root is never taken.
Therefore,
Variance = Summation of square of differences between observation and the mean divided by the number of observations.
That is,
Variance = {(87-78)^2 + (46-78)^2 + (90-78)^2 + (78-78)^2 + (89-78)^2}/5 = 274
A) AB turn clockwise to coincide with BC
= ABD + DBC
= 33.3° + 30.6°
= 63.9°
b) If E is drawn directly opposite C.
EBC is a straight line, so sum of angles =180°
ABE + ABD + DBC = 180°
ABE + 33.3° + 30.6° = 180°
ABE + 63.9° = 180°
ABE = 180 - 63.1
ABE = 116.9°
Hope this explains it.
