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1 year ago

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How many zeroes are at the end of $42!$ (42 factorial)? (Reminder: The number $n!$ is the product of the integers from 1 to $n$.

For example, $5!=5\cdot 4\cdot3\cdot2\cdot 1= 120$.)

1 answer:

Dovator [93]1 year ago

4 0

Answer:

47 zeros

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given:

The average yearly salary of a lawyer is $24 thousand less than twice that of an architect.

Combined, an architect and a lawyer earn $ 210 thousand.

Now, to find the average yearly salary of an architect and a lawyer.

Let the average yearly salary of an architect be $x.$

So, the average yearly salary of the lawyer = $2x-24,000.$

Combined, architect and lawyer earn = $\$210,000.$

Now, to get the average salary of the architect and lawyer:

$x+(2x-24000)=210000$

$x+2x-24000=210000\\\\3x-24000=210000$

<em>Adding both sides 24000 we get:</em>

$3x=186,000\\\\Dividing\ both\ sides\ by\ 3\ we\ get:\\\\x=62000.$

<u>The average salary of architect = $62,000.</u>

Now, to get the average salary of lawyer by substituting the value of $x$ :

$2x-24000\\\\=2(62000)-24000\\\\=124000-24000\\\\=\$100,000.$

<u>The average salary of lawyer = $100,000.</u>

Therefore, the average yearly salary of the architect is $62,000 and the lawyer is $100,000.

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Step-by-step explanation:

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