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2 years ago

14

How many zeroes are at the end of $42!$ (42 factorial)? (Reminder: The number $n!$ is the product of the integers from 1 to $n$.

For example, $5!=5\cdot 4\cdot3\cdot2\cdot 1= 120$.)

1 answer:

Dovator [93]2 years ago

4 0

Answer:

47 zeros

Step-by-step explanation:

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