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Murljashka [212]
2 years ago
13

Stacey owns a lot that has 180 feet of front footage and contains 36,000 square feet. She purchases two lots adjacent to each si

de of his lot. These side lots are each 200 feet deep and contain 19,000 square feet. What is the total front footage of all three lots?
Mathematics
2 answers:
vlabodo [156]2 years ago
7 0
<h2>The total front footage of all three lots is 370 ft</h2>

Step-by-step explanation:

Front footage of first lot = 180 ft

Area of each side lot = 19000 ft²

Depth of each side lot = 200 ft

We have

           Area = Depth x Front footage

           19000 = 200 x Front footage

           Front footage = 95 ft

Total front footage = Front footage of first lot + 2 x Front footage of each side lot

Total front footage = 180 + 2 x 95

Total front footage = 180 + 190

Total front footage = 370 ft

The total front footage of all three lots is 370 ft

bija089 [108]2 years ago
3 0
The graph of the function f(x)=(x+2)(x+6) is shown

The statement the function is negative for all real values of x where x <-2
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For a specific species of fish in a pond, a wildlife biologist wants to build a regression equation to predict the weight of a f
sashaice [31]

Answer: First of all, we will add the options.

A. Yes, because 3 inches falls above the maximum value of lengths in the sample.

B. Yes, because the regression equation is based on a random sample.

C. Yes, because the association between length and weight is positive.

D. No, because 3 inches falls above the maximum value of lengths in the sample.

E. No, because there may not be any 3-inch fish of this species in the pond.

The correct option is D.

Step-by-step explanation: It would not be appropriate to use the model to predict the weight of species that is 3 inches long because 3 inches falls above the maximum value of lengths in the sample.

As we can see from the question, the model only accounts for species that are within the range of 0.75 to 1.35 inches in length, and species smaller or larger than that length have not been taken into consideration. Therefore the model can not be used to predict the weights of fishes not with the range accounted for.

3 0
1 year ago
If PR = 4x – 2 and RS = 3x – 5, which expression represents PS?
klasskru [66]

Answer:

PS = 7x- 7

Step-by-step explanation:

Given

Straight Line, PS

Such that

PR = 4x -2

RS = 3x - 5

Required

Find PS

From the attachment above, it can be seen that RS is a continuation of PS;

This implies that

PS = PR + RS

Substitute PR = 4x -2 and RS = 3x - 5

PS = 4x - 2 + 3x - 5

Collect like terms

PS = 4x + 3x- 2  - 5

PS = 7x- 7

Hence, the length of PS is PS = 7x- 7

8 0
1 year ago
Enzo is studying the black bear population at a large national park.
Naddik [55]

Answer:

2,973

Step-by-step explanation:

The black bear population B(t), in the park is modeled by the following function:

B(t) = 2500 \cdot 2^{0.01t}

Where t is the time(in years) elapsed since the beginning of the study.

We want to determine the black bear population in 25 years time, t=25.

B(25) = 2500 \cdot 2^{0.01*25}\\=2973.02\\\approx 2973

There will be 2,973 black bears in 25 years time.

4 0
1 year ago
What is the value of the 2s in 42,256
Anna71 [15]
2,000 and 200 are the values of the 2s in 42256

4 0
1 year ago
Read 2 more answers
A rectangular piece of land is 40m long and 25m wide. A path of uniform width and 426 m^2 area sorrounds
fredd [130]

Answer:

Width of the uniform path that surrounds the piece of land = 3 m

Step-by-step explanation:

Let the width of the path that surrounds the piece of land be x.

The situation described is sketched in the attached image to this solution.

The dimension of the Length of the piece of land including the uniform path that surrounds it = (40 + 2x) m

The Breadth of the piece of land including the uniform path that surrounds it = (25 + 2x) m

The area of the piece of land including the uniform path that surrounds it

= (Area of the piece of land) + (Area of the uniform path that surrounds it)

Area of the piece of land = Length × Breadth = 40 × 25 = 1000 m²

Area of the uniform path that surrounds it = 426 m² (Given in the question)

The area of the piece of land including the uniform path that surrounds it = 1000 + 426 = 1426 m²

But the area of the piece of land including the uniform path that surrounds it is also

= (Length of the piece of land including the uniform path that surrounds it) × (Breadth of the piece of land including the uniform path that surrounds it

= (40 + 2x) + (25 + 2x)

= 1000 + 80x + 50x + 4x²

= (4x² + 130x + 1000) m²

Equation these 2 areas

4x² + 130x + 1000 = 1426

4x² + 130x - 426 = 0

Solving the quadratic equation

x = 3 or -35.5

Since the width cannot be negative,

x = 3 m

Hope this Helps!!!

7 0
2 years ago
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