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Elenna [48]
2 years ago
8

A candidate scored 32 marks out of 80.find his percentage score​

Mathematics
1 answer:
Radda [10]2 years ago
7 0

Answer:

40%

Step-by-step explanation:

Take the amount over the total

32/80

.4

Change to percent form by multiplying by 100

40 %

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There are seven boys and five girls in a class. The teacher randomly selects three different students to answer questions. The f
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The probability of picking one girl would be \frac{5}{12}. That is because there are 5 girls out of the 12 students, and the probability of an event occuring is: \frac{\text{# of things you want}}{\text{# of things are possible}}.

Using that same logic, the next student should be easier. We reduced the student population by 1, so we have 11 possible ways it can happen now instead of 12, so that gives us:\frac{7}{11}, for the probability of picking a boy as the second pick.

And lastly, using the same logic shown above, the probability of picking a girl on the third pick would be:\frac{4}{10}.

We are not done, though. We have the separate probabilities, but now we have to multiply then together to figure out the probability of this exact event happening:

\frac{5}{12}*\frac{7}{11}*\frac{4}{10}=\frac{140}{1320}

Which when reduced is:

\frac{7}{66}

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1 year ago
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The parent function f(x) = x3 is represented by graph A. Graph A is transformed to get graph B and graph C. Write the functions
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Graph B represents the function g(x)=x^3-2 Graph C represents the function h(x)=2x^3
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2 years ago
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△ABC has vertices A(−1, 6), B(2, 10), and C(7, −2) . Find the measure of each angle of the triangle. Round decimal answers to th
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Answer:

<A = 90°, <B = 71.6° <C = 18.4°

Step-by-step explanation:

Given the vertices of a △ABC to be A(−1, 6), B(2, 10), and C(7, −2)

Before we can get each angle of the triangle, we need to get its sides first.

Using the formula fie finding the distance between two points

D = √(x2-x1)²+(y2-y1)²

For side AB:

Given A(−1, 6), B(2, 10)

AB = √{2-(-1)}²+(10-6)²

AB =√3²+4²

AB = √25

AB = 5

For side AC:

Given A(-1,6) and C(7, −2)

AC = √{7-(-1)}²+(-2-6)²

AC = √8²+8²

AC = √128

AC = √64×2

AC = 8√2

For side BC:

Given B(2,10) and C(7, −2)

BC = √(7-2)²+(-2-10)²

BC = √5²+12²

BC = √25+144

BC = √169

BC = 13

First we need to get theta using cosine rule

|AC|² = |AB|+|BC| - 2|AB||AC| cos theta

(8√2)² = 5²+13²-2(5)(13)cos theta

128 = 169-130costheta

128-169 = -130costheta

-41= -130costheta

Costheta = -41/-130

Cos theta = 0.315

theta = arccos 0.315

theta = 71.64°

<B = 71.6°

Using sine rule to get <A,

BC/sin A = AC/sinB

13/sinA = 8√2/sin71.6°

8√2sinA = 13sin71.6°

SinA = 12.34/8√2

SinA = 1.09°

A = arcsin1

<A = 90.0°

<C = 180°-(71.6+90)

< C = 180-161.6

<C = 18.4°

3 0
1 year ago
a group of girls bought 72 rainbow hairbands ,144 brown and black hairbands and 216 bright colored hairbands .what is the larges
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Answer:

72

Step-by-step explanation:

We are assuming that all girls in the group bought the same number of items.

Therefore, we need to find the highest common factor of 72, 144 and 216.

HCF

72 = 2 * 2 * 2 * 3 * 3

144 = 2 * 2 * 2 * 2 * 3 * 3

216 = 2 * 2 * 2 * 3 * 3 * 3

The product of the emboldened numbers is the highest common factor.

That is:

2 * 2 * 2 * 3 * 3 = 72

Therefore, the largest possible number of girls in the group is 72.

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The following Venn Diagram shows the results of a teacher survey. A teacher asked her class which students owned android phones,
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Answer: 0.60

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