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stiks02 [169]
2 years ago
11

A jar of sweets contains 5 yellow sweets, 4 red sweets, 8 green sweets, 4 orange sweets and 3 white sweets. Ola chooses a sweet

at random. What is the probability that she will pick either a yellow or orange sweet?
Mathematics
1 answer:
Lorico [155]2 years ago
7 0

Answer:

Probability to pick yellow or orange sweet = 3 / 8

Step-by-step explanation:

Given:

Number of yellow sweet = 5

Number of red sweet = 4

Number of green sweet = 8

Number of orange sweet = 4

Number of white sweet = 3

Find:

Probability to pick yellow or orange sweet

Computation:

Total number of sweets = 24 sweets

Probability to pick yellow = 5 / 24

Probability to pick orange = 4 / 24

Probability to pick yellow or orange sweet = 5/24 + 4 / 24

Probability to pick yellow or orange sweet = 9 / 24

Probability to pick yellow or orange sweet = 3 / 8

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<h2>Therefore he took 40 gram of 1^{st} type solution and 10 gram of 2^{nd} type solution.</h2>

Step-by-step explanation:

Given that , A pharmacist 13% alcohol solution another 18% alcohol solution .

Let he took x gram solution of 1^{st} type solution

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According to problem

⇔\frac{ [x\times\frac{13}{100}] +[(50 -x) \times\frac{18}{100} ]}{50}= \frac{14}{100}

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Therefore he took 40 gram of 1^{st} type solution and (50 -40)gram = 10 gram of 2^{nd} type solution.

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olasank [31]
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