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2 years ago

Which values of c will cause the quadratic equation –x2 + 3x + c = 0 to have no real number solutions? Check all that apply.

2 answers:

4 0

A quadratic equation has no real number solutions than the discriminant is less than zero

D < 0

(b^2 -4ac) < 0

(9 -4(-1*c) < 0

(9+4c) < 0

4c < -9

c < -9/4

hope this will help you

Sophie [7]2 years ago

4 0

Which values of c will cause the quadratic equation –x2 + 3x + c = 0 to have no real number solutions? Check all that apply.

–5,-9/2

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Mary weighs n kg while her sister weighs 15 kg less. How many times is Mary heavier than her sister?

kari74 [83]

Answer:

Mary is $\frac{n}{n-15}$ times heavier than her sister

Step-by-step explanation:

Mary's Weight = n

Sister's Weight = n - 15

To find how many times mary is heavier, we need to multiply "that many time" [let it be x] with sister's weight to get Mary's weight.

<u>e.g. </u>If someone weighs 100 and another person 50, 50 * 2 = 100, thus, 100 kg person is 2 times heaving. We do same for this:

(n - 15) * x = n

x = n/(n - 15)

3 0

1 year ago

Read 2 more answers

G A professor has two light bulbs in his garage. When both are burned out, they are replaced, and the next day starts with two w

Aneli [31]

Answer:

2/7 or 0.2857

Step-by-step explanation:

The expected time before the first bulb burns out (two bulbs working) is given by the inverse of the probability that a bulb will go out each day:

$E_1 = \frac{1}{0.02}=50\ days$

The expected time before the second bulb burns out (one bulb working), after the first bulb goes out, is given by the inverse of the probability that the second bulb will go out each day:

$E_2 = \frac{1}{0.05}=20\ days$

Therefore, the long-run fraction of time that there is exactly one bulb working is:

$t=\frac{E_2}{E_1+E_2}=\frac{20}{20+50}\\t=\frac{2}{7}=0.2857$

There is exactly one bulb working 2/7 or 0.2857 of the time.

7 0

2 years ago

A mouse traveled a total distance of 3/24 of a mile in a maze over the past three hours the mouse travel the same distance each

alexgriva [62]

Answer:

Total distance mouse traveled in 3 hours = $\frac{3}{24}$ of a mile

The mouse traveled the same distance in each hour. So in order to find the distance covered in 1 hour we have to divide the distance covered in 3 hours by 3. This will give us the distance that the mouse traveled in one hour.

So, the distance traveled in one hour will be = $\frac{3}{24} \div 3 = \frac{3}{24} \times \frac{1}{3} =\frac{1}{24}$ of a mile

The error which Matt made was that he divided only the denominator of the expression by 3, this probably was a calculation error.

Correct conclusion will be: Mouse travel 1/24 of a mile each hour

8 0

2 years ago

You ride your bicycle 40 meters. How many complete revolutions does the front wheel make?

Delicious77 [7]

First, we convert the given radius of the wheel to meters giving us an answre of 0.325 m. Then, we calculate for the circumference.
C = 2πrr
Substituting,
C = 2π(0.325 m) = 2.04 m
Then, we have a road that is 40 m long, the number of complete revolutions is,
n = 40/2.04 m = 20

7 0

2 years ago

What is the length of segment XY?

Brilliant_brown [7]

Answer:

StartRoot 53 EndRoot units

XY = √53

Step-by-step explanation:

Choose which is point 1 and point 2 so you don't confuse the coordinates.

Point 1 (–4, 0) x₁ = –4 y₁ = 0

Point 2 (3, 2) x₂ = 3 y₂ = 2

Use the formula for the distance between two points.