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2 years ago

Sheila places a 54 square inch photo behind a 12-inch-by-12-inch piece of matting.

Mathematics

1 answer:

nata0808 [166]2 years ago

3 0

The are of a rectangle is calculated by multiplying the length and the width of the shape. First, we determine the dimensions of this figure. We do as follows:

Width = 12 - 2x - 2x = 12 - 4x
Length = 12 - x - x = 12 - 2x

Area = (Length)(Width)
Area = (12 - 2x )(12-2x)

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rodikova [14]

Volume of cone = 1/3 x pi x r^2 x h
where r = 5 ft and h = 16ft

Volume = 1/3 x pi x 5^2 x 16 = 400/3 π ft^3

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2 years ago

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In a forest, 20% of mushrooms are red, 50% brown, and 30% white. A red mushroom is poisonous with a probability of 20%. A mushro

kirill115 [55]

Draw a simple branch diagram to work the probabilities out. You find that the chance of a poisonous mushroom is 0.08 and the chance of a red poisonous is 0.04. So the probability that a poisonous mushroom is red is 1/2 or 0.5.

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A flat circular plate has the shape of the region x squared plus y squared less than or equals 1x2+y2≤1. the plate, including t

vredina [299]

You're looking for the extreme values of $x^2+3y^2+13x$ subject to the constraint $x^2+y^2\le1$ .

The target function has partial derivatives (set equal to 0)

$\dfrac{\partial(x^2+3y^2+13x)}{\partial x}=2x+13=0\implies x=-\dfrac{13}2$

$\dfrac{\partial(x^2+3y^2+13x)}{\partial y}=6y=0\implies y=0$

so there is only one critical point at $\left(-\dfrac{13}2,0\right)$ . But this point does not fall in the region $x^2+y^2\le1$ . There are no extreme values in the region of interest, so we check the boundary.

Parameterize the boundary of $x^2+y^2\le1$ by

$x=\cos u$

$y=\sin u$

with $0\le u$ . Then $t(x,y)$ can be considered a function of $u$ alone:

$t(x,y)=t(\cos u,\sin u)=T(u)$

$T(u)=\cos^2u+3\sin^2u+13\cos u$

$T(u)=3+13\cos u-2\cos^2u$

$T(u)$ has critical points where $T'(u)=0$ :

$T'(u)=-13\sin u+4\sin u\cos u=\sin u(4\cos u-13)=0$

$(1)\quad\sin u=0\implies u=0,u=\pi$

$(2)\quad4\cos u-13=0\implies\cos u=\dfrac{13}4$

but $|\cos u|\le1$ for all $u$ , so this case yields nothing important.

At these critical points, we have temperatures of

$T(0)=14$

$T(\pi)=-12$

so the plate is hottest at (1, 0) with a temperature of 14 (degrees?) and coldest at (-1, 0) with a temp of -12.

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1 year ago

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fredd [130]

The are 6 possible outcomes because there are 6 tiles.

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2 years ago

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