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REY [17]
2 years ago
6

Each ? below represents a factor between 1 and 9

Mathematics
1 answer:
bearhunter [10]2 years ago
7 0
Where is it? I can’t help you without it.
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Identify 1 and 2. Select all that apply of the following terms: acute, right, obtuse, adjacent, vertical, complementary, supplem
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Right angle and complementary. this cold be wrong.
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1 year ago
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Henry wants to double a cake recipe that uses 2 cups and 10 tbsp of flour. How much flour will he need?
Lubov Fominskaja [6]

Answer:

20 tbsp of flour OR 1.25 or 1 \frac{1}{4} cups of flour

Step-by-step explanation:

10 tbsp of flour

*2

____________

20 tbsp of flour OR 1.25 or 1 \frac{1}{4} cups of flour

5 0
1 year ago
Your promotional budget for the year is $300 for personal selling, $300 for sales promotion, \$1,500 for advertising, and $500 f
aleksandr82 [10.1K]

Answer:

to get the total promotion budget for the year we will add $300 for personal selling plus $300 for sales promotion plus $1500 for advertising plus $500 for image promotion to the a total of 2600 dollars

8 0
1 year ago
Eli invested $ 330 $330 in an account in the year 1999, and the value has been growing exponentially at a constant rate. The val
Cloud [144]

Answer:

The value of the account in the year 2009 will be $682.

Step-by-step explanation:

The acount's balance, in t years after 1999, can be modeled by the following equation.

A(t) = Pe^{rt}

In which A(t) is the amount after t years, P is the initial money deposited, and r is the rate of interest.

$330 in an account in the year 1999

This means that P = 330

$590 in the year 2007

2007 is 8 years after 1999, so P(8) = 590.

We use this to find r.

A(t) = Pe^{rt}

590 = 330e^{8r}

e^{8r} = \frac{590}{330}

e^{8r} = 1.79

Applying ln to both sides:

\ln{e^{8r}} = \ln{1.79}

8r = \ln{1.79}

r = \frac{\ln{1.79}}{8}

r = 0.0726

Determine the value of the account, to the nearest dollar, in the year 2009.

2009 is 10 years after 1999, so this is A(10).

A(t) = 330e^{0.0726t}

A(10) = 330e^{0.0726*10} = 682

The value of the account in the year 2009 will be $682.

4 0
2 years ago
Evaluate 8a-1+0.5b8a−1+0.5b8, a, minus, 1, plus, 0, point, 5, b when a=\dfrac14a=
professor190 [17]

Answer: 6

Step-by-step explanation:

Given the following expression:

8a-1+0.5b

You need to substitute the given values of "a" and "b" into the expression. Notice that these values are:

a=\frac{1}{4}\\\\b=10

Then;

 8a-1+0.5b=8(\frac{1}{4})-1+0.5(10)

Now you must solve the multiplications:

=\frac{8}{4}-1+5=2-1+5

The final step is to add the numbers. Therefore, you get the following answer:

=6

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2 years ago
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