Each ? below represents a factor between 1 and 9

the number 792 and 990, written as the product of their prime factors are 792 = 23 x 32 x 11 and 990 = 2 x 9 x 5 x 1. Hence, fin

noname [10]

Answer:

198

Step-by-step explanation:

4 0

2 years ago

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Brant is preparing for the upcoming track season, and he wants to reduce the time of his 1-mile run. Last year, he conducted an

Ivanshal [37]

The Q30X program and the Intensity program are both effective because the average participant 1-mile run time was reduced for each program, but the Intensity program is the more effective program because it yielded a greater decrease in the average participant 1-mile run time.

5 0

2 years ago

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Suppose that 90% of all dialysis patients will survive for at least 5 years. In a simple random sample of 100 new dialysis patie

Keith_Richards [23]

Answer:

The probability $P(\^ p > 0.80) = 0.99957$

Step-by-step explanation:

From the question we are told that

The population proportion is p = 0.90

The sample size is n = 30

Generally mean of the sampling distribution is $\mu_{\= x } = p = 0.90$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{\frac{p( -p )}{n} }$

=> $\sigma = \sqrt{\frac{0.90( 1 -0.90 )}{100} }$

=> $\sigma = 0.03$

Generally the he probability that the proportion surviving for at least five years will exceed 80%, rounded to 5 decimal places is mathematically represented as

$P(\^ p > 0.80) = P(\frac{ \^ p - p }{ \sigma } > \frac{0.80 - 0.90}{0.03} )$

Generally $\frac{\^p - p}{\sigma} = Z(The standardized \ value \ of \^ p)$

So

$P(\^ p > 0.80) = P(Z > -3.33 )$

From the z-table $P(Z > -3.33 ) = 0.99957$

So

$P(\^ p > 0.80) = 0.99957$

5 0

2 years ago

How to draw a picture that represents 24 divided by 6

olasank [31]

Draw a cake or a pie cut into 24 pieces. Then draw 6 figures around the cake. color code each group of 4 pieces of cake and coordinate it with figure.

Ex: If 4 pieces of the cake were red, color one of the figures red so each figure gets 4 pieces of the cake.

8 0

2 years ago

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A box contains 5 red and 5 blue marbles. Two marbles are withdrawn randomly. If they are the same color, then you win $1.10; if

topjm [15]

Answer:

a) The expected value is $\frac{-1}{15}$

b) The variance is $\frac{49}{45}$

Step-by-step explanation:

We can assume that both marbles are withdrawn at the same time. We will define the probability as follows

#events of interest/total number of events.

We have 10 marbles in total. The number of different ways in which we can withdrawn 2 marbles out of 10 is $\binom{10}{2}$ .

Consider the case in which we choose two of the same color. That is, out of 5, we pick 2. The different ways of choosing 2 out of 5 is $\binom{5}{2}$ . Since we have 2 colors, we can either choose 2 of them blue or 2 of the red, so the total number of ways of choosing is just the double.

Consider the case in which we choose one of each color. Then, out of 5 we pick 1. So, the total number of ways in which we pick 1 of each color is $\binom{5}{1}\cdot \binom{5}{1}$ . So, we define the following probabilities.