Answer:
1.4in
Step-by-step explanation:
Length of Photo = 4in
Width of Photo = 3in
Unknown:
Value of X = ?
Solution:
Follow these steps:
Area of a rectangle = l x w
Since the photo is a rectangle; area of photo:
Area of photo = 4in x 3in = 12in²
For the area of the ad;
Length of ad = 4 + x
Width of ad = 3 + x
Given that,
the area of the photo =
area of ad
12in² =
area of ad
Area of ad = 24in²
Area of the ad;
(4 + x) (3 + x) = 24
12 + 4x + 3x + x² = 24
12 + 7x + x² = 24
x² + 7x = 24 - 12
x² + 7x = 12
x² + 7x - 12 = 0
Using the almighty formula where
a = 1, b = 7 and c = -12
x = 
x =
or ![\frac{-7 - \sqrt[]{-7^{2} - 4x1x-12 } }{2x1}](https://tex.z-dn.net/?f=%5Cfrac%7B-7%20-%20%5Csqrt%5B%5D%7B-7%5E%7B2%7D%20-%204x1x-12%20%7D%20%7D%7B2x1%7D)
x = 1.4 or -8.4
therefore the answer is 1.4in
x is 1.4in
Answer:
Step-by-step explanation:
x, height of men is N(69, 2.8)
Sample size n =150
Hence sample std dev = 
Hence Z score = 
A) Prob that a random man from 150 can fit without bending
= P(X<78) = P(Z<3.214)=1.0000
B) n =75
Sample std dev = 
P(X bar <72) = P(Z<9.28) = 1.00
C) Prob of B is more relevent because average male passengers would be more relevant than a single person
(D) The probability from part (b) is more relevant because it shows the proportion of flights where the mean height of the male passengers will be less than the door height.
The first term is x^4.
The second term is 8x^3
Answer: The first equation is an equation of a parabola. The second equation is an equation of a line.
Explanation:
The first equation is,

In this equation the degree of y is 1 and the degree of x is 2. The degree of both variables are not same. Since the coefficients of y and higher degree of x is positive, therefore it is a graph of an upward parabola.
The second equation is,

In this equation the degree of x is 1 and the degree of y is 1. The degree of both variables are same. Since both variables have same degree which is 1, therefore it is linear equation and it forms a line.
Therefore, the first equation is an equation of a parabola. The second equation is an equation of a line.
Answer:
1. Take the Average of the distances the ball travelled each hit.
2. He should use the Interquartile Range. This is the difference between the Upper Quartile and the Lower Quartile of the distances he hits the ball.
3. He should use Mean
4. He should use Median. It best measures skewed data
Step-by-step explanation:
THE FIRST PART.
Raul should take the average of the distances the ball travelled each hit.
This is done by summing the total distances the ball travelled each bounce, and then dividing the resulting value by the total number of times he hit the ball, which is 10.
THE SECOND PART
He should use the Interquartile Range. This is the difference between the Upper Quartile and the Lower Quartile of the distances he hits the ball.
THE THIRD PART
He should take the mean of the distances of the ball that stayed infield.
This is the distance that occurred the most during the 9 bounces that stayed infield. The one that went outfield is makes it unfair to use any other measure of the center, taking the mean will give a value that is significantly below his efforts.
THE FOURTH PART
He should take the Median of the data, it is best for skewed data.
This is the middle value for all the distances he recorded.