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Helga [31]
2 years ago
12

In ΔSTU, the measure of ∠U=90°, ST = 9.7 feet, and US = 4 feet. Find the measure of ∠T to the nearest degree.

Mathematics
1 answer:
BaLLatris [955]2 years ago
5 0

Answer:

Around 24 degrees

Step-by-step explanation:

*Make sure calculator is on degree mode*

Try to draw out triangle--it helps

Need to use law of sines... this is where an angle and the side that opposes it are equal to each other. For example, Angle U is equal to 9.7

\frac{sin\alpha }{4} = \frac{sin90}{9.7}

Multiply 4 and sin90 and then divide the product by 9.7

Use sin^{-1} on calculator to convert the answer into degrees

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Of the total number of people on a cruise ship, 1/4 or child passengers. 2/5 of the remaining people were crew. There were 1320
Nuetrik [128]
<h2>462</h2>

Step-by-step explanation:

       Total number of people on the cruise ship was 1320.

\frac{1}{4}^{th} of the people were child passengers. Number of child passengers = \dfrac{1}{4}\times (\text{Total number of people})=\dfrac{1}{4}\times 1320=330

\frac{2}{5}^{th} of the people were crew. Number of people that were crew = \dfrac{2}{5}\times (\text{Total number of people})=\dfrac{2}{5}\times 1320=528

       Remaining people in the ship constitute the adult passengers.

       Number of adult passengers = (\textbf{Total number of people})-(\textbf{Total number of children})-(\textbf{Total number of crew})=1320-330-528=\textbf{462}

∴ Number of adult passengers = 462

5 0
2 years ago
Each month a retail store awards a blue ribbon to its employee of the month. The probability that Chloe is the employee of the m
klasskru [66]

Answer:

37%

Step-by-step explanation:

6 0
2 years ago
A control chart is developed to monitor the analysis of iron levels in human blood. The lines on the control chart were obtained
sergejj [24]

Answer:

Step-by-step explanation:

Hello!

The variable is X: iron level on human blood.

It has a mean of μ= 51.50 mg/dl and a standard deviation of σ= 3.50 mg/dl.

According to the control chart, the process should be shut down for troubleshooting when the analysis shows values X[bar]≥ 53.42 mg/dl and X[bar]≤ 49.58 mg/dl

Warnings are received at levels X[bar]≥52.78 mg/dl and X[bar]≤ 50.22 mg/dl

The system works between levels 49.58<X[bar]<53.42 and works without warnings between 50.22<X[bar]<52.78.

Using these parameters you have to analyze if the lists of sample means to see which ones are within the working values are wich ones are outside this interval.

<u>Sample 1</u>

Min= 50.15

Max= 51.99

Mean= 51.61

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>This sample's min value is below the lower limit of the warning interval but not low enough to reach action levels, the max value is within the working range.</em>

<em><u /></em>

<u>Sample 2 </u>

Min= 50.32

Max= 52.56

Mean= 51.16

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both the max and min values of the sample are within the working range without warning.</em>

<em />

<u>Sample 3</u>

Min= 50.25

Max= 53.12

Mean= 51.83

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>The max value of this sample is above the upper limit of the warning interval but does not surpass the upper bond of the troubleshoot interval. Min value is within working values.</em>

<em />

<u>Sample 4</u>

Min= 50.05

Max= 53.01

Mean= 51.70

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both min and max values surpass the warning interval but do not reach action levels</em>.

<u>Sample 5</u>

Min= 50.35

Max= 52.71

Mean= 51.37

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both min and max values are within working levels without warnings.</em>

<em />

Considering that samples reaching warning levels should be shut down as a precaution, they are classified as:

Shutdown: Sample 1, 3 and 4

Do not shutdown: Sample 2 and 5.

I hope it helps!

8 0
2 years ago
A battery factory typically produces 12,000 batteries per day and uses 50 boxes for packing the batteries. If the number of boxe
weqwewe [10]

Answer:

25 more boxes is needed

Step-by-step explanation:

12000 batteries require 50 boxes. Let's find the unit rate.

That is, how many batteries are in each box??

That's 12,000/50!

12,000/50 = 240 batteries per box

Now, to find how many boxes we would need for 18,000 batteries, we will have to divide the total (18000) by 240(number of batteries per box). That is:

18,000/240 = 75 boxes

We would need 75 boxes to pack 18,000 batteries.

We want "how many MORE boxes needed", so we will the excess:

75 - 50 = 25 more boxes is needed

4 0
1 year ago
Last Month the electric meter reading was 7985 kWh. This month the reading was 8328 kWh. If electricity costs P3.40 per kWh,how
Ivahew [28]
8328kWh-7985kWh=343kWh\\\\343\ \times\ 3.40=1166.20\leftarrow answer
7 0
2 years ago
Read 2 more answers
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