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Helga [31]
2 years ago
12

In ΔSTU, the measure of ∠U=90°, ST = 9.7 feet, and US = 4 feet. Find the measure of ∠T to the nearest degree.

Mathematics
1 answer:
BaLLatris [955]2 years ago
5 0

Answer:

Around 24 degrees

Step-by-step explanation:

*Make sure calculator is on degree mode*

Try to draw out triangle--it helps

Need to use law of sines... this is where an angle and the side that opposes it are equal to each other. For example, Angle U is equal to 9.7

\frac{sin\alpha }{4} = \frac{sin90}{9.7}

Multiply 4 and sin90 and then divide the product by 9.7

Use sin^{-1} on calculator to convert the answer into degrees

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Christopher bought a new watch at the store when they were having a 30% off sale.If the regular price of the watch was $48, how
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Answer:

30 \div 100 \times 48 = 14.4 \\ 48 - 14.4 = 33.6

therefore Christopher paid $ 33.6

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1 year ago
What are the terms of each expression 3a-19
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James defines a circle as "the set of all the points equidistant from a given point." His statement is not precise enough becaus
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It is 4.7 km from Lighthouse A to Port B. The bearing of the port from the lighthouse is N73°E. A ship has sailed due west from
Gennadij [26K]

Answer:

correct option is  C. 3.7 km

Step-by-step explanation:

given data

A to Port B = 4.7 km

lighthouse = N73°E

lighthouse = N31°E

solution

we get here first  \angle B and  

here

\angle A = 90 - 73 = 17°

\angle B =  73 - 31 = 42°

and

sum of all angle 180° so

\angle A +  

17° + 42° +  \angle C = 180°  

solve it we get

\angle C = 121°

Now we use here sin law that is

\frac{b}{sinB} = \frac{c}{sinC}   ........................2

put here value and we get

\frac{b}{sin42} = \frac{4.7}{sin121}  

solve it we get

b = 3,7 km

so correct option is  C. 3.7 km

7 0
2 years ago
Of 560 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compared
frutty [35]

Answer:

a) (0.5256,0.5944)  

c) Criticism is invalid

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 560

Proportion of mislabeled = 56%

\hat{p} = 0.56

a) 90% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.64

Putting the values, we get:

0.56\pm 1.64(\sqrt{\dfrac{0.56(1-0.56)}{560}}) = 0.56\pm 0.0344\\\\=(0.5256,0.5944)

b) Interpretation of confidence interval:

We are 90% confident that the true proportion of all seafood in the country that is mislabeled or misidentified is between 0.5256 and 0.5944 that is 52.56% and 59.44%.

c) Validity of criticism

Conditions for validity:

np > 10\\n(1-p)>10

Verification:

560\times 0.56 = 313.6>10\\560(1-0.56) = 246.4>10

Both the conditions are satisfied. This, the criticism is invalid.

8 0
2 years ago
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