Answer:
18.67% of bills are greater than $131
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What proportion of bills are greater than $131
This proportion is 1 subtracted by the pvalue of Z when X = 131. So



has a pvalue of 0.8133
1 - 0.8133 = 0.1867
18.67% of bills are greater than $131
Answer:
Darius is correct if only the median score is considered.
Step-by-step explanation:
Darius scores are; 96, 54,120, 87, 123
arrange the scores in increasing order;
54,87,96,120,123
mean = (54+87+96+120+123)/5 =480/5 =96
median =96
Barb's scores are 92,94,96,98,110
mean=(92,94,96,98,110)/5 =490/5=98
median score=96
⇒if the median score only is considered; then it is a tie because the score is 96 in both players.
Answer:

Step-by-step explanation:
we know that
The surface area of the cone is given by the formula

where
r is the radius of the base
l is the slant height
we have

substitute


Ceiling Function is the least integer that is greater than or equal to x.
Question:
You are in a bike race. When you get to the first checkpoint, you are 2/5 of the distance to the second checkpoint. When you get to the second check point, you are 1/4 of the distance to the finish. If the entire race is 40 miles, what is the distance between the start and the first check point?
Answer: 4 miles
Step-by-step explanation:
Let distance between start to first checkpoint = x
First checkpoint to second checkpoint = 2/5 of x
Distance of start to checkpoint 1 = ( 2/5 of start to checkpoint 2)
Distance of start to checkpoint 2 = (1/4 of start to finish)
If start to checkpoint 2 = 1/4 of start to finish
Then,
Distance of start to checkpoint 1 = ( 2/5 * 1/4 of start to finish)
Distance of start to checkpoint 1 = 2/20 of start to finish = 1/10 of start to finish
Entire race = 40 miles = distance from start to finish
1/ 10 of 40
= ( 1/10) × 40
= 4 miles