The answer to the problem is as follows:
Count all boys as one unit. Then there is one boy and 2 girls who can be permuted in 3! = 6 ways. Bout the 3 boys can permute among themselves in 3! = 6 ways.
<span>6x6 = 36 ways in which all boys are together.
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Answer:
D.)
15040000 <= k <=19840000
Step-by-step explanation:
V = 1200 -0.00002k
Value V after one year falls in the range of $803.20 and $899.20.
Let's substract these values from 1200.
1200-803.20=396.80
1200-899.20=300.80
So it means that
0.00002k= 396.80
And
0.00002k= 300.80
So
0.00002k= 396.80
K= 396.80/0.00002
K= 19840000
And
0.00002k= 300.80
K = 300.80/0.00002
K= 15040000
So range is between
15040000 <= k <=19840000
answer is (-7,-9)
step by step:-
S is the midpoint of RT so ,
s=
, 
, 
, 
R= (-7,-9)
Answer:
20.33%
Step-by-step explanation:
We have that the mean (m) is equal to 87.5, the standard deviation (sd) 6.25 and the sample size (n) = 12
They ask us for P (x <86)
For this, the first thing is to calculate z, which is given by the following equation:
z = (x - m) / (sd / (n ^ 1/2))
We have all these values, replacing we have:
z = (86 - 87.5) / (6.25 / (12 ^ 1/2))
z = -0.83
With the normal distribution table (attached), we have that at that value, the probability is:
P (z <-0.83) = 0.2033
The probability is 20.33%
1. x= 11.7 μ = 7
2. z11.7= 1.3
3. Is 11.7 within a z-score of 3?
a. Yes because z11.7 < 3.
4. Which statement is true of z11.7?
b. z11.7 is between 1 and 2 standard deviations of the mean.
