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Nezavi [6.7K]
1 year ago
13

On your lab bench, you have 2 mystery metal cubes. each cube has a mass of 10.0 grams. cube a has a density of 10 g/cm3. cube b

has a density of 0.37 cm3. what conclusion can be made about the sizes of the two cubes?
a. cube b has atoms that are more closely packed in its volume than cube
a.
b. cube b has a volume that is one-third of the volume of cube
a.
c. each edge of cube b is two times larger than cube
a.
d. each edge of cube b is three times larger than cube
Mathematics
1 answer:
lianna [129]1 year ago
6 0
To compare both, we find the volume of both cubes as follows:

V of cube A = 10 g / 10 g/cm^3 = 1 cm^3

V of cube B = 10 g / 0.37 g/cm^3 = 27 cm^3

I think the correct answer from the choices listed above is option D. Each edge of cube b is three times larger than cube. Hope this helps. Have a nice day.
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Here is a picture that shows one side of a child's wooden block with a semicircle cut out at the bottom. What is the area of the
ehidna [41]

Answer:

30.7 cm² (nearest tenth)

Step-by-step explanation:

Area of the wooden block = area of rectangle - area of semi-circle

Area of Rectangle = length × width

Length = 9 cm

Width = 4.5 cm

Area of rectangle = 40.5 cm²

Area of semi-circle = ½(πr²)

Radius (r) = ½ of diameter = ½*5 = 2.5 cm

π = 3.14

Area of semi-circle = ½(3.14*2.5²)

Area of semi-circle = 9.8125 cm²

✅Area of the wooden block = 40.5 - 9.8125 = 30.7 cm² (nearest tenth)

7 0
1 year ago
An Exhibitor is selling decorative wreaths at an arts and craft show. The net profit P in dollars from the sales of the Wreaths
Svetradugi [14.3K]

<u>Given</u>:

An Exhibitor is selling decorative wreaths at an arts and craft show.

The net profit P in dollars from the sales of the Wreaths is given by P(n)=0.75n-50 , where N is the number of wreaths sold.

We need to determine the number of wreaths sold to earn a net profit of $100.

<u>Number of wreaths sold:</u>

The number of wreaths sold to earn a profit of $100 can be determined by substituting P(n) = 100 in the equation P(n)=0.75n-50, we get;

100=0.75n-50

150=0.75n

\frac{150}{0.75}=n

200=n

Thus, the number of wreaths sold is 200.

5 0
1 year ago
If the odds of catching the flu among individuals who take vitamin C is 0.0342 and the odds of catching the flu among individual
melamori03 [73]

Answer:

Correct option (A).

Step-by-step explanation:

The probability of an individual catching a flu when he or she has taken vitamin C is, P (F|C) = 0.0342.

The probability of an individual catching a flu when he or she has not taken vitamin C is, P (F|C') = 0.2653.

Th ratio of individuals who caught the flu when they did not take vitamin C to those who took vitamin C is:

=\frac{P(F|C')}{P(F|C)}\\ =\frac{0.2653}{0.0342} \\=7.7573

This implies that:

P(F|C')=7.7573\times P(F|C)

Thus, the the individuals not taking vitamin C are 7.7573. Times more likely to catch the flu than individuals taking vitamin C.

The statement is True.

4 0
1 year ago
We would like to know the velocity of the block when it reaches some position x. Finding this requires an integration. However,
Slav-nsk [51]

Answer:

An alternative definition for the acceleration ax that can be written in terms of v_x and \frac{dv_x}{dx} is a_x=v_x \frac{dv_x}{dx}

Step-by-step explanation:

We know that :

a_x=\frac{dv_x}{dt}

Now we are supposed to find an alternative definition for the acceleration ax that can be written in terms of v_x and \frac{dv_x}{dx}

So, We will use chain rule over here :

a_x=\frac{dv_x}{dt}\\a_x=\frac{dv_x}{dt} \times \frac{dx}{dx}\\a_x=\frac{dv_x}{dx} \times \frac{dx}{dt}\\a_x=\frac{dv_x}{dx} \times \frac{dx}{dt}  [\frac{dx}{dt}=v_x]\\a_x=\frac{dv_x}{dx} \times v_x\\a_x=v_x\frac{dv_x}{dx}

Hence an alternative definition for the acceleration ax that can be written in terms of v_x and \frac{dv_x}{dx} is a_x=v_x \frac{dv_x}{dx}

4 0
2 years ago
Calculate the value of x to one decimal place. inches
kakasveta [241]

Use the law of cosines: c^2=a^2+b^2-2ab\cos C

We have:

c=x\\a=3in\\b=7in\\C=54^o

substitute:

\cos54^o\approx0.5878\\\\c^2=3^2+7^2-2\cdot3\cdot7\cdot0.5878\\\\c^2=9+49-24.6876\\\\c^2=33.3129\to c=\sqrt{33.3129}\\\\c\approx5.8

5 0
2 years ago
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