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2 years ago

13

Nicholas and Elaine are planning to serve cheesecake for dessert at their wedding and have purchased twelve cheesecakes. If the

cheesecakes are divided evenly among the 125 wedding guests, how much cheesecake will each guest receive?

1 answer:

Svet_ta [14]2 years ago

6 0

12 cheesecakes

125 wedding guests

125 divided by 12=10.41666666666667=10.4

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1 year ago

Which classification best represents a triangle with side lengths 6 cm, 10 cm, and 12 cm? acute, because 62 + 102 < 122 acute

maw [93]

The Pythagoras theorem states that
the sum of squares of the shorter sides (legs) of a right triangle equals the square of the third side.

A corollary from the same theorem helps us solve this problem:
If the sum of the squares of the shorter sides of a triangle is greater than the square of the third side, the included angle is acute. ..... (case 1)
Conversely, if the sum of the squares of the shorter sides of a triangle is less than the square of the third side, the triangle is obtuse. .....(case 2)

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Therefore case 2 applies, and the triangle is obtuse.

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2 years ago

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BigorU [14]

Answer:

I suppose it should be

6b² and (6b²)²

or

6b² and 36 $b^{4}$

Step-by-step explanation:

(a+b)² = a² + 2ab + b²

therefore

(6b²+2a)² = (6b²)² + 12ab² + 4a²

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2 years ago

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In the parallelogram AXYZ, line segment AT = 4y – 2, line segment TY = 6x -12, line segment TX = 14, line segment ZT = 2x + 12.

Tpy6a [65]

In a parallelogram diagonals bisect each other,
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2 years ago

Ten major recording acts are able to play at the stadium. If the average profit margin for a concert is $175,000, how much would

nikitadnepr [17]

Answer: Total amount the stadium would clear for all of these events combined is $1750000

Step-by-step explanation:

Since we have given that

Number of major recording acts are able to play at the stadium = 10

Average profit margin for a concert = $175000

We need to find the amount that the stadium clear for all of these events combined

As we know the formula for "Average"

$Average=\frac{\text{ Total sum}}{\text{ Number of recording acts }}\\\\175000=\frac{\text{total sum}}{10}\\\\175000\times 10=Total\ sum\\\\\$1750000=Total\ sum$

Hence, total amount the stadium would clear for all of these events combined is $1750000.

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