Lamont builds a triangular shape fence to hide his pool pump

David is 22 years old. He buys 100/300/50 liability insurance, collision insurance with a $100 deductible, and comprehensive ins

sesenic [268]

Answer:$2139.25

Step-by-step explanation: Took the test

5 0

2 years ago

Ramon has 6.75 kg coffee. he wants 0.25 kg bags. how many bags does he need?

Hatshy [7]

Answer:

Ramon would need 27 bags

Step-by-step explanation:

This is because if you divide 6.75 by 0.25 you would get 27

5 0

2 years ago

A science test, which is worth 100 points, consists of 24 questions. Each question is worth either 3 points or 5 points. If x is

Arada [10]

Answer:

The test contains 10 three-point questions and 14 five-point questions.

Step-by-step explanation:

The value of x is the number of 3-point questions, and the value of y is the number of 5-point questions, as the problem statement tells you. So, the solution (x, y) = (10, 14) indicates ...

"The test contains 10 three-point questions and 14 five-point questions."

_____

You can try the offered answers to see which might apply. The last choice has too many questions. The first and third choices don't add up to 100 points.

7 0

2 years ago

Read 2 more answers

Please answer all of them need this

VikaD [51]

First Question

For a better understanding of the solution provided here please find the first attached file which has the diagram of the the isosceles trapezoid.

We dropped perpendiculars from C and D to intersect AB at Q and P respectively.

As can be seen in $\Delta BCQ$ , we can easily find the values of CQ and BQ.

Since, $Sin(75^0)=\frac{CQ}{8}$

$\therefore CQ=8\times Sin(75^0)\approx 7.73$ ft

In a similar manner we can find BQ as:

$Cos(75^0)=\frac{BQ}{8}$

$BQ\approx2.07$ ft

All these values can be found in the diagram attached.

Thus, because of the inherent symmetry of the isosceles trapezoid, PQ can be found as:

$PQ=22-(AP+QB)=22-(2.07+2.07)=17.86$

Let us now consider $\Delta AQC$

We can apply the Pythagorean Theorem here to find the length of the diagonal AC which is the hypotenuse of $\Delta AQC$ .

$AC=\sqrt{(AQ)^2+(QC)^2}=\sqrt{(AP+PQ)^2+(QC)^2}=\sqrt{(2.07+17.86)^2+(7.73)^2}\approx21.38$ feet.

Thus, out of the given options, Option B is the closest and hence is the answer.

Second Question

For this question we can directly apply the formula for the area of a triangle using sines which is as:

Area= $\frac{1}{2}$ (First Side)(Second Side)(Sine of the angle between the two sides)

Thus, from the given data,

Area= $\frac{1}{2}\times 218.5\times 224.5\times sin(58.2^0)\approx20845$ $m^2$

Therefore, Option D is the correct option.

Third Question

For this question we will apply the Sine Rule to the $\Delta ABC$ given to us.

Thus, from the triangle we will have:

$\frac{AB}{Sin(\angle C)}=\frac{BC}{Sin(\angle A)}$

$\frac{c}{Sin(\angle C)}=\frac{a}{Sin(\angle A)}$

$\frac{17}{Sin(25^0)}=\frac{a}{Sin(45^0)}$

This gives $a$ to be:

$a\approx28.44$

Which is not close to any of the given options.

Fourth Question

Please find the second attachment for a better understanding of the solution provided her.

As can be clearly seen from the attached diagram, we can apply the Cosine Rule here to find the return distance of the plane which is CA.

$AC=\sqrt{(AB)^2+(BC)^2-2(AB)(BC)\times Cos(\angle B)}$

$\therefore AC=\sqrt{(172.20)^2+(111.64)^2-2(172.20)(111.64)\times Cos(177.29^0)}\approx283.8$ miles.

Thus, Option D is the answer.

8 0

2 years ago

Read 2 more answers

The graph shows the rate at which the depth of the water in a pond is changing over time. On a coordinate plane, a graph titled

lawyer [7]

Answer:

Step-by-step explanation:

The key to solving this question is to find the distance bwtween the two points given

distance=y2-y1/x2-x1

(2,4)(4,8)

2=x1,4=y1

4=x2

8=y2

8-4/4-2

4/2=2

The depth of the water is increasing by 2 ft each minute

4 0

2 years ago