Answer:
<em>t=60</em>
Step-by-step explanation:
3/2t-16=4/3t-6
(subtract 4/3t from both sides)
3/2t-16-4/3t=-6
(add 16 to both sides)
3/2t-4/3t=-6+16
(simplify)
1/6t=10
(divide by 1/6 (or multiply by 6 on both sides)
t=60
Total surface area of the cylinder= 2*area of base+lateral area=
=2*1962.5 + <span>194.2 = 4119.2 cm²
1m=100 cm
1m² = (100 cm)²
1m²=10000cm²
</span>4119.2 cm² *(1m²/10000 cm²)= 0.41192 m²
Answer:
- Time = approximately mid 2012
- Oil import rate = 3600 barrels
Step-by-step explanation:
<h3><em>Unclear part of the question</em></h3>
- I(t) = −35t² + 800t − 1,000 thousand barrels per day (9 ≤ t ≤ 13)
- According to the model, approximately when were oil imports to the country greatest? t = ?
<h3>Solution</h3>
Given the quadratic function
- <em>The vertex of a quadratic function is found by a formula: x = -b/2a</em>
<u>As per given function:</u>
<u>Then</u>
- t = - 800/2*(-35) = 11.43 which is within given range of 9 ≤ t ≤ 13
This time is approximately mid 2012.
<u>Considering this in the function, to get oil import rate for the same time:</u>
- l(11.43) = -35*(11.43)² + 800*11.43 - 1000 = 3571.4285
<u>Rounded to two significant figures, the greatest oil import rate was</u>:
Im pretty sure its
m=/0 because when m is 0 then f(x) does not depend on the value of x.
Hope this helped!
