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2 years ago

How to classify 17/10

2 answers:

7 0

Real numbers encompass three classifications of numbers, which we'll talk about in a little bit. Whole numbers, rational numbers, and irrational numbers are all real numbers. Imaginary numbers are not real numbers. They are complex numbers that are written as a real number multiplied by an imaginary unit (

storchak [24]2 years ago

4 0

Answer:

rational

Step-by-step explanation:

You might be interested in

Solve the given initial value problem and determine how the interval in which the solution exists depends on the initial value y

zalisa [80]

Answer:

y has a finite solution for any value y_0 ≠ 0.

Step-by-step explanation:

Given the differential equation

y' + y³ = 0

We can rewrite this as

dy/dx + y³ = 0

Multiplying through by dx

dy + y³dx = 0

Divide through by y³, we have

dy/y³ + dx = 0

dy/y³ = -dx

Integrating both sides

-1/(2y²) = - x + c

Multiplying through by -1, we have

1/(2y²) = x + C (Where C = -c)

Applying the initial condition y(0) = y_0, put x = 0, and y = y_0

1/(2y_0²) = 0 + C

C = 1/(2y_0²)

1/(2y²) = x + 1/(2y_0²)

2y² = 1/[x + 1/(2y_0²)]

y² = 1/[2x + 1/(y_0²)]

y = 1/[2x + 1/(y_0²)]½

This is the required solution to the initial value problem.

The interval of the solution depends on the value of y_0. There are infinitely many solutions for y_0 assumes a real number.

For y_0 = 0, the solution has an expression 1/0, which makes the solution infinite.

With this, y has a finite solution for any value y_0 ≠ 0.

8 0

2 years ago

Carlie runs two different business. She needs to pay $100 for materials, and pay her associates $12 per hour for

Marrrta [24]

Answer:

$375+12ct_c+10lt_l$

Step-by-step explanation:

Carlie is running two different business.

She needs to pay:

- For the childcare business,

100$ for the materials

12$ per hour for each associate for her childcare business, so if we call:

$t_c$ = the number of hours worked by each associate

$c$ = the number of associates

The total cost for the childcare business is:

$C=100+12ct_c$ (1)

- For the lawn care business,

275$ for the materials

10$ per hour for each associate for her lawn care business, so if we call:

$t_l$ = the number of hours worked by each associate

$l$ = the number of associates

The total cost for the lawn care business is:

$L=275+10lt_l$ (2)

Therefore, the total expenses from both businesses is the sum of (1) and (2):

$T=C+L=100+12ct_c+275+10lt_l = 375+12ct_c+10lt_l$

3 0

2 years ago

A rate that describes how much smaller or larger the scale drawing is than the real object

AfilCa [17]

It is called a scale factor :)

8 0

2 years ago

A graduate weighs 35.825 g. When 10 mL of water are measured in it, the weight of the graduate and water is 45.835 g. Calculate

erik [133]

Answer:

Calculated weight of water = 10.01 g

percentage error = 0.1%

Step-by-step explanation:

Given:

Weight of graduate = 35.825 g

Weight of graduate + Water = 45.835 g

Now,

The weight of water = ( Weight of graduate + Water ) - Weight of graduate

The weight of water = 45.835 - 35.825

The weight of water = 10.01 g

Now,

The percentage of error = $\frac{\textup{Calculated value - Actual value}}{\textup{Actual value}}\times100$

The percentage error = $\frac{\textup{10.01 - 10}}{\textup{10}}\times100$

The percentage error = 0.1%

3 0

2 years ago

The box office took in a total of $2905 in paid admissions for the high-school musical. Adult tickets cost $8 each, and student

Svet_ta [14]

There are no equations to choose from but it should look like the following.

a= # of adult tickets
s= # of student tickets

QUANTITY EQUATION
a + s= 560

COST EQUATION
$8a + $3s= $2905

***If you have to also solve for the number of adults and students, here are the steps.

STEP 1:
multiply quantity equation by -8

-8(a + s)= -8(560)
-8a - 8s= -4480

STEP 2:
add cost equation and step 1 equation

$8a + $3s= $2905
-8a - 8s= -4480
a term cancels out to zero
-5s= -1575
divide both sides by -5
s= 315 students

STEP 3:
substitute s=315 in quantity equation
a + s= 560
a + 315= 560
subtract 315 from both sides
a= 245 adults

ANSWER:
Quantity Equation
a + s= 560

Cost Equation
$8a + $3s= $2905

Hope this helps! :)

7 0

2 years ago