Question

What is a simplified form of -(14x)^0y^-7z

Answer 1

Answer:

$\frac{1}{y^{7z}}$

Step-by-step explanation:

Given the expression:

$-(14)^0 \cdot y^{-7z}$

We know that:

$a^0 =1$

$a^{-1} = \frac{1}{a}$

then;

$1 \cdot y^{-7z}$

⇒$y^{-7z}$

⇒$\frac{1}{y^{7z}}$

Therefore, the simplified form of $-(14)^0 \cdot y^{-7z}$ is, $\frac{1}{y^{7z}}$.

Answer 2

Anything to the power of 0 is one.

Therefore we have:

(1)(y^-7z)

Which simplifies to:

y^-7z