All categories

2 years ago

What is a simplified form of -(14x)^0y^-7z

Mathematics

2 answers:

vagabundo [1.1K]2 years ago

7 0

Answer:

$\frac{1}{y^{7z}}$

Step-by-step explanation:

Given the expression:

$-(14)^0 \cdot y^{-7z}$

We know that:

$a^0 =1$

$a^{-1} = \frac{1}{a}$

then;

$1 \cdot y^{-7z}$

⇒ $y^{-7z}$

⇒ $\frac{1}{y^{7z}}$

Therefore, the simplified form of $-(14)^0 \cdot y^{-7z}$ is, $\frac{1}{y^{7z}}$ .

GenaCL600 [577]2 years ago

3 0

Anything to the power of 0 is one.

Therefore we have:

(1)(y^-7z)

Which simplifies to:

y^-7z

You might be interested in

Let x = 8.99999 . (a) Is x < 9 or is x = 9? x < 9 It is neither; x > 9 x = 9 x < 9 and x = 9 It cannot be determined

qaws [65]

Answer: idk

Step-by-step explanation:

idk

4 0

2 years ago

A study is planned to compare the proportion of men who dislike anchovies with the proportion of women who dislike anchovies. Th

andrey2020 [161]

Answer:

The requirements are satisifed since we have the proportion estimated, the sample sizes provided, we assume random sampling for the selection of the data and the distribution for the difference of proportions can be considered as normal

$z=\frac{0.67-0.84}{\sqrt{0.755(1-0.755)(\frac{1}{41}+\frac{1}{56})}}=-1.923$

Step-by-step explanation:

Data given and notation

$n_{M}=41$ sample of male selected

$n_{W}=56$ sample of demale selected

$p_{M}=0.57$ represent the proportion of men who dislike anchovies

$p_{WCB}=0.84$ represent the proportion of women who dislike anchovies

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the proportion for men is different from women , the system of hypothesis would be:

Null hypothesis: $p_{M} = p_{W}$

Alternative hypothesis: $p_{M} \neq p_{W}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}$ (1)

Where $\hat p=\frac{X_{M}+X_{W}}{n_{M}+n_{W}}=\frac{0.67+0.84}{2}=0.755$

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.67-0.84}{\sqrt{0.755(1-0.755)(\frac{1}{41}+\frac{1}{56})}}=-1.923$

4 0

2 years ago

An algebra tile configuration. Only the Product spot is shown. 8 tiles are in the Product spot in 3 columns with 3 rows. First r

tamaranim1 [39]

Answer:

i think its a

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Lisa has $150 at most to spend on clothes. She wants to buy a pair of jeans for $58 and will spend the rest on t-shirts that cos

anzhelika [568]

Answer:

14t + 58 ≤ 150

Step-by-step explanation:

If she cannot spend more than what she has, which is 150, the inequality sign has to be "less than or equal to". It's ok if she spends less than 150, but not ok if she spends more, because she doesn't have it to spend.

We know the cost of 1 pair of jeans is 58. Now she wants to make up the difference by getting as many $14 shirts as possible (the number of shirts being our unknown).

That means that the cost of the jeans PLUS the unknown number of shirts cannot exceed 150.

Therefore, the inequality is:

14t + 58 ≤ 150

4 0

2 years ago

Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i

jenyasd209 [6]

Answer:

If the limit that you want to find is $\lim_{x\to \infty}\dfrac{P(x)}{Q(x)}$ then you can use the following proof.

Step-by-step explanation:

Let $P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0}$ and $Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0}$ be the given polinomials. Then

$\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}$

Observe that

$\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}$

and

$\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}$

Then

$\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}$

3 0

2 years ago