answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vitfil [10]
2 years ago
12

A freight company has shipping orders for two products. The first product has a unit volume of 10 cu ft, and it weighs 50 lbs. T

he second product's unit volume is 3 cu ft, and it weighs 40 lbs. If the company's trucks have 2300 cu ft of space and can carry 21,000 lbs., how many units of each can be transported in a single shipment with one truck?
Mathematics
1 answer:
Lady_Fox [76]2 years ago
8 0

Answer:

116 units of the first product

380 units of the second product

Step-by-step explanation:

Product 1 has a unit volume of  10 cu ft

Product 2 has a unit volume of 3 cu ft

The truck has 2300 cu ft of space

Product 1 weighs 50 lbs

Product 2 weighs 40 lbs

The truck can carry 21000 lbs

Let X be the units of product 1

Let Y be the units of product 2

The given information can be expressed as:

10X+3Y=2300...(1)

50X+40Y=21000...(2)

Solving the system of equations:

10X+3Y=2300...(1)

10X=2300-3Y

X=(2300-3Y)/10

Substituting X in (2) we have:

50X+40Y=21000

50[(2300-3Y)/10]+40Y=21000

50[(2300/10)-(3Y/10)]+40Y=21000

50[230-(3Y/10)+40Y=21000

11500-(150Y/10)+40Y=21000

11500-15Y+40Y=21000

11500+25Y=21000

25Y=21000-11500

25Y=9500

Y=380

Substituting Y in (1) we have:

10X+3Y=2300...(1)

10X+3(380)=2300

10X+1140=2300

10X=2300-1140

10X=1160

X=116

So 116 units of the first product and 380 units of the second product can be transported in a single shipment with one truck.

You might be interested in
The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 22
NISA [10]

Answer:

a) v(2\,s) = 2.9\,\frac{m}{s}, b) v(4\,s) = -16.7\,\frac{m}{s}, c) t = 2.296\,s, d) h (2.296\,s) = 27.829\,m, e) t \approx 4.679\,s, f) v(4.679\,s) = -23.354\,\frac{m}{s}

Step-by-step explanation:

The velocity function can be derived by the differentiating the height function:

v = 22.5-9.8\cdot t

Velocities after 2 and 4 seconds are, respectively:

a) v(2\,s) = 2.9\,\frac{m}{s}

b) v(4\,s) = -16.7\,\frac{m}{s}

The maximum height is reached when velocity is zero. Then:

22.5-9.8\cdot t = 0

c) t = 2.296\,s

The maximum height is:

d) h (2.296\,s) = 27.829\,m

The time required to hit the ground is:

-4.9\cdot t^{2}+22.5\cdot t +2 = 0

Roots of the second-order polynomial are:

t_{1} \approx 4.679\,s

t_{2} \approx -0.087\,s

Only the first root is physically reasonable.

e) t \approx 4.679\,s

The velocity when the projectile hits the ground is:

f) v(4.679\,s) = -23.354\,\frac{m}{s}

7 0
2 years ago
Xavier is a salesperson who is paid a fixed amount of $455 per week. He also earns a commission of 3% on the sales he makes. If
melomori [17]
Xavier wants to earn more then 575 dollars a week, he will have to sale x<3,600 a week . So the answer is C
5 0
2 years ago
The price of a ceramic bead necklace (Y) is directly proportional to the number of beads (x) on the necklace. Using the graph, w
Annette [7]

Answer: C) (1,0.80) represents the unit rate. E) (25,20) represents the price of a necklace with 25 beads

Step-by-step explanation:

(1, 0.80) represents the unit rate.

(25, 20) represents the price of a necklace with 25 beads.

\frac{y}{x} = unit rate → \frac{4}{5} = 0.80; \frac{12}{15} = 0.80; \frac{16}{20} = 0.80

Point (1, r) → (1, 0.80) represents the unit rate.

25(0.80) = 20; thus, (25, 20) represents the price of 25 beads.

Hope this helps

8 0
2 years ago
A satellite makes 4 revolutions of the earth in one day. How many revolutions would it make in 6 1/2 days?
koban [17]
26. 
1 day/24 hours, makes 4 revolutions. 
4 x 6 = 24, 
1/2 of 4 = 2.
24+2 = 26. 
26 revolutions, if my answer is wrong someone please correct me.
8 0
2 years ago
A common assumption in modeling drug assimilation is that the blood volume in a person is a single compartment that behaves like
mixas84 [53]

Answer:

a) \mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}

b) \mathbf{x = 2000 - 2000e^{-0.015t}}

c)  the  steady state mass of the drug is 2000 mg

d) t ≅ 153.51  minutes

Step-by-step explanation:

From the given information;

At time t= 0

an intravenous line is inserted into a vein (into the tank) that carries a drug solution with a concentration of 500

The inflow rate is 0.06 L/min.

Assume the drug is quickly mixed thoroughly in the blood and that the volume of blood remains constant.

The objective of the question is to calculate the following :

a) Write an initial value problem that models the mass of the drug in the blood for t ≥ 0.

From above information given :

Rate _{(in)}= 500 \ mg/L  \times 0.06 \  L/min = 30 mg/min

Rate _{(out)}=\dfrac{x}{4} \ mg/L  \times 0.06 \  L/min = 0.015x \  mg/min

Therefore;

\dfrac{dx}{dt} = Rate_{(in)} - Rate_{(out)}

with respect to  x(0) = 0

\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}

b) Solve the initial value problem and graph both the mass of the drug and the concentration of the drug.

\dfrac{dx}{dt} = -0.015(x - 2000)

\dfrac{dx}{(x - 2000)} = -0.015 \times dt

By Using Integration Method:

ln(x - 2000) = -0.015t + C

x -2000 = Ce^{(-0.015t)

x = 2000 + Ce^{(-0.015t)}

However; if x(0) = 0 ;

Then

C = -2000

Therefore

\mathbf{x = 2000 - 2000e^{-0.015t}}

c) What is the steady-state mass of the drug in the blood?

the steady-state mass of the drug in the blood when t = infinity

\mathbf{x = 2000 - 2000e^{-0.015 \times \infty }}

x = 2000 - 0

x = 2000

Thus; the  steady state mass of the drug is 2000 mg

d) After how many minutes does the drug mass reach 90% of its stead-state level?

After 90% of its steady state level; the mas of the drug is 90% × 2000

= 0.9 × 2000

= 1800

Hence;

\mathbf{1800 = 2000 - 2000e^{(-0.015t)}}

0.1 = e^{(-0.015t)

ln(0.1) = -0.015t

t = -\dfrac{In(0.1)}{0.015}

t = 153.5056729

t ≅ 153.51  minutes

4 0
1 year ago
Other questions:
  • he time spent dancing (minutes) and the amount of calories burned can be modeled by the equation c = 5.5t. Which table of values
    11·4 answers
  • Harold walks 3/4 mile in each 5/6 hour. Calculate Harold's unit rate. Explain how you found your answer.
    5·1 answer
  • You are selling a mobile app for $10 per user per month.if you get 7 users every month starting with 10 in the first month.how m
    13·1 answer
  • (1 point) Consider the paraboloid z=x2+y2. The plane 2x−2y+z−8=0 cuts the paraboloid, its intersection being a curve. Find "the
    5·1 answer
  • In a science test devi scores 15 marks more than lixin . If devi obtains twice as many marks as lexin . Find the number of marks
    5·1 answer
  • A government bureau keeps track of the number of adoptions in each region. The accompanying histograms show the distribution of
    7·1 answer
  • Jeff has 8 red marbles, 6 blue marbles, and 4 green marbles that are the same size and
    7·2 answers
  • A researcher wishes to examine the relationship between years of schooling completed and the number of pregnancies in young wome
    10·1 answer
  • PLEASE HELP
    11·1 answer
  • Ben starts walking along a path at 2 mi/h. One and a half hours after Ben leaves, his sister Amanda begins jogging along the sam
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!