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slavikrds [6]
2 years ago
5

Harold walks 3/4 mile in each 5/6 hour. Calculate Harold's unit rate. Explain how you found your answer.

Mathematics
1 answer:
emmainna [20.7K]2 years ago
6 0
To solve this problem, you must apply the proccedure shown below:

 1. The problem gives the following information: <span>Harold walks 3/4 miles in each 5/6 hours. Therefore, you have to divide  3/4 miles by 5/6 hours, as below:

 unit rate=(3/4)(5/6)
 unit rate=(3x6)(4x5)
 unit rate=18/20 

 3. When you simplify, you obtain:

 unit rate=9/10

 4. Therefore, as you can see, the answer is: Harold's unit rate is 9/10.</span>
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Answer:

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Step-by-step explanation:

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H = \dfrac{(u_{\text{v}})^{2}}{2a} = \dfrac{8.66^{2}}{2\times 9.8} =\textbf{3.83 m}

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1. Calculate the time of flight

Use the vertical component of velocity to calculate the time to the maximum height of the stream.

u_{\text{v}} = at\\t = \dfrac{ u_{\text{v}}}{a} = \dfrac{\text{8.66 m$\cdot$s}^{-1}}{\text{9.8 m$\cdot$s}^{-2}}= \text{0.884 s}

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Time of flight = 2t = 2 × 0.884 s  = 1.77 s

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s = vt = 5 m·s⁻¹ × 1.77 s = 8.84 m  

You should place the drain 8.84 m from the pipe.}

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The stream of water will hit the drain with the same velocity as when it left the pipe.

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A zookeeper is monitoring the population of birds. The flock needs to have exactly three times more females than males to thrive
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Answer:

The constraints are

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