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podryga [215]
2 years ago
9

HURRYYY HELP! Triangle ABC is congruent to triangle FDE, and both triangles have the same orientation, as shown. What is the slo

pe of DF, which also the slope of AC?

Mathematics
1 answer:
muminat2 years ago
8 0
We know that
point A(1,1) C(3,5)
point D(-2,-4) F(0,0)

step 1
find the slope FD
m=(y2-y1)/(x2-x1)------> m=(0+4)/(0+2)----> m=4/2----> m=2

step 2
find the slope AC
m=(y2-y1)/(x2-x1)------> m=(5-1)/(3-1)----> m=4/2-----> m=2

mAC=mFD

the answer is
the slope FD is 2
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Answer:

A. True

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The Triangle Inequality Theorem says that the sum of any two sides must be greater than the third side. Let's see if this is true.

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puteri [66]

Answer:

The interval of the decreasing function is (-∞ , -1) ⇒ g(x)

The interval of the decreasing function is (-∞ , 0) ⇒ f(x)

Step-by-step explanation:

* Lets explain how to solve it

- Decreasing function means a function with a graph that moves

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- For example, any line with a negative slope is decreasing function

- Lets look to the attached graph to understand the meaning of the

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∵ f(x) = IxI ⇒ green graph

∵ g(x) = Ix + 1I - 7 ⇒ purple graph

- From the graph f(x) translated 1 unit to the left and 7 units down to

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- The domains of f(x) and g(x) are all real numbers {x : x ∈ R}

- The range of f(x) is {y : y ≥ 0}

- The range of g(x) is {y : y ≥ -7}

# For f(x)

- The slope of the green line from (-∞ , 0) is negative

- The slope of the green line from (0 , ∞) is positive

# For g(x)

- The slope of the purple line from (-∞ , -1) is negative

- The slope of the purple line from (-1 , ∞) is positive

∵ The line with negative slope represent decreasing function

∴ The interval of the decreasing function is (-∞ , -1) ⇒ g(x)

∴ The interval of the decreasing function is (-∞ , 0) ⇒ f(x)

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2 years ago
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Step-by-step explanation:

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2 years ago
Read 2 more answers
A quality control technician works in a factory that produces computer monitors. Each day, she randomly selects monitors and tes
jeka94

Answer:

There is enough evidence to support the claim that the true proportion of monitors with dead pixels is greater than 5%.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 300

p = 5% = 0.05

Alpha, α = 0.05

Number of dead pixels , x = 24

First, we design the null and the alternate hypothesis  

H_{0}: p = 0.05\\H_A: p > 0.05

This is a one-tailed(right) test.  

Formula:

\hat{p} = \dfrac{x}{n} = \dfrac{24}{300} = 0.08

z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

Putting the values, we get,

z = \displaystyle\frac{0.08-0.05}{\sqrt{\frac{0.05(1-0.05)}{300}}} = 2.384

Now, we calculate the p-value from excel.

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Conclusion:

Thus, there is enough evidence to support the claim that the true proportion of monitors with dead pixels is greater than 5%.

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dmitriy555 [2]

Answer:

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Step-by-step explanation:

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Surface area of triangular prism = 2.5(6)+15(8)

Surface area of triangular prism = 15 + 120

Surface area of triangular prism = 135mm²

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