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Makovka662 [10]
2 years ago
12

If the measure of angle ACB is 90°, then which expression represents the value of g? triangle ACB, point E is on segment AC betw

een points A and C and point D is on segment BC between points B and C, creating segment ED, CE equals h, EA equals j, CD equals k, DB equals m, ED equals g, and AB equals f
g equals f over 2
g = 2f
g equals j over h
g equals k over m

Mathematics
1 answer:
Ulleksa [173]2 years ago
3 0

Answer:

g=\frac{f}{2}

Step-by-step explanation:

The picture of the question in the attached figure

In this problem i will assume that point E is the midpoint AC and point D is the midpoint BD

so

we know that

The <u><em>Triangle Midpoint Theorem</em></u> states that the segment joining two sides of a triangle at the midpoints of those sides, is parallel to the third side and is half the length of the third side

In this problem the segment ED joining two sides of a triangle at the midpoints of those sides

so

ED is parallel to AB and ED is half the length of AB

ED=\frac{1}{2}AB

we have

AB=f\\ED=g

substitute the given values

g=\frac{f}{2}

Guest
1 year ago
so whats the answer
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Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.3 minutes and a standard deviation of 3.3 minutes. This means that \mu = 8.3, \sigma = 3.3.

(a) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes?

We are working with a sample mean of 37 jets. So we have that:

s = \frac{3.3}{\sqrt{37}} = 0.5425

Total time of 320 minutes for 37 jets, so

X = \frac{320}{37} = 8.65

This probability is the pvalue of Z when X = 8.65. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.65 - 8.3}{0.5425}

Z = 0.65

Z = 0.65 has a pvalue of 0.7422. This means that there is a 74.22% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

(b) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes?

Total time of 275 minutes for 37 jets, so

X = \frac{275}{37} = 7.43

This probability is subtracted by the pvalue of Z when X = 7.43

Z = \frac{X - \mu}{\sigma}

Z = \frac{7.43 - 8.3}{0.5425}

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Z = -1.60 has a pvalue of 0.0548.

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(c) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes?

Total time of 320 minutes for 37 jets, so

X = \frac{320}{37} = 8.65

Total time of 275 minutes for 37 jets, so

X = \frac{275}{37} = 7.43

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From b), we have that for X = 7.43, we have Z = -1.60, that has a pvalue of 0.0548.

So there is a 0.7422 - 0.0548 = 0.6874 = 68.74% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes.

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