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2 years ago

The homoskedasticity-only F-statistic and the heteroskedasticity-robust F-statistic typically are:

Mathematics

1 answer:

LiRa [457]2 years ago

6 0

Answer:

The homoskedasticity-only F-statistic and the heteroskedasticity-robust F-statistic typically are different.

Step-by-step explanation:

An F statistic is a value derived by running an ANOVA test or a regression analysis to find out if the means between two populations are significantly different.

The homoskedasticity-only” F-statistic is derived by running two regressions, one under the null hypothesis and one under the alternative hypothesis. If the “unrestricted” model fits sufficiently better, reject the null.

In the first regression, the restricted regression (the null hypothesis) is forced to be true. This is the regression in which all the coefficients are set to zero; the relevant regressors are excluded from the regression. In the second regression, the unrestricted regression, the alternative hypothesis is allowed to be true. If the sum of squared residuals is sufficiently smaller in the unrestricted than the restricted regression, then the test rejects the null hypothesis

The heteroskedasticity-robust F-statistic is built in to STATA (“test” command); this tests all q restrictions at once.

The homoskedasticity-only F-statistic is important historically (and also in practice), and can help intuition, but isn’t valid when there is heteroskedasticity

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$290, 12.5%, 6 months

Veronika [31]

The information shown here only shows a principal sum, a rate of interest and a period or time. There is no question as to what is needed. But suppose the need is for simple interest, then we calculate using the given information and the formula: I = PRT where I is simple interest, P is the principal, R is the rate per year, and T is time P = 290, T is 6 months which is 0.5 years, R = 12.5 % which is written as 0.125 in decimal fraction. I = 290 × 0.125 x 0.5 → I = 18.125 Therefore after 6 months , the interest earned will be 18. 125 dollars

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2 years ago

Melissa wants to make a table representing the area of her vegetable garden for a variety of different lengths of the tomato pat

Ksenya-84 [330]

Answer:

$\begin{array}{cc}Length \ of \ Tomato \ Patch \ (in \ feet)&Area \ of \ Vegetable \ Garden \ (in \ square \ feet)\\\ [6.25]&338\\6.5&[242.625]\\ \ [6.75]&147.25\\7&[51.875]\end{array}$

Step-by-step explanation:

The date from the given table, is expressed as follows;

Area of Vegetable Garden (in square feet); 338, ___, 147.25, ___

Length of Tomato Patch (in feet); ___, 6.5, ___, 7

The length of the tomato patch increases with decrease in the area of the garden

Given that the length of the tomato patch is the independent variable, we can have;

Length of Tomato Patch (in feet); 6.25, 6.5, 6.75, 7

Therefore, for an increase in the length of the tomato patch from 6.25 to 6.75, (a change of Δl = 0.5) the area of the vegetable garden decreased from 338 to 147.25 which is a decrease of ΔA = 190.75

Therefore, the width of the tomato patch, w = ΔA/Δl = 190.75/0.5 = 381.5

The width of the tomato patch, w = 381.5 ft.

The relationship between the total area, TA, the area of the vegetable garden, <em>A</em>, and the length of the tomato patch, <em>l</em>, is therefore, given as follows;

A = TA - 381.5·l

338 = TA - 381.5×6.25

TA = 338 + 381.5×6.25 = 2,722.375

Therefore, when l = 6.5, we get

A = 2,722.375 - 381.5×6.5 = 242.625

When l = 7, we get

A = 2,722.375 - 381.5×7 = 51.875

Therefore, we get;

$\begin{array}{cc}Length \ of \ Tomato \ Patch \ (in \ feet)&Area \ of \ Vegetable \ Garden \ (in \ square \ feet)\\\ [6.25]&338\\6.5&[242.625]\\ \ [6.75]&147.25\\7&[51.875]\end{array}$

5 0

1 year ago

Holly bought 23 tickets to the baseball game. She got a group rate that gave her $4 off of the regular ticket price for each tic

sveticcg [70]

Answer:

The regular price of the ticket was $12.

Step-by-step explanation:

Let us call $P$ the regular price of the tickets, and if she had bought tickets at this price, the total cost would have been

$23P$ .

But Holly got $4 off the regular ticket price, that means one ticket cost her

$P-4$

and if she bought 23 tickets it cost her

$23(P-4)$

and we are told this equals $184; therefore we have

$23(P-4)=184$

now we solve this equation the following way:

$23(P-4)=184$

$23P-4(23)=184$

$23P-92=184$

$23P=276$

$\boxed{ P=12}$

Thus, the regular price was $12.

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2 years ago

Read 2 more answers

Olivia had math and reading homework tonight. Olivia can solve each math problem in 1 minute and she can read each page in 1.5 m

ziro4ka [17]

Answer: the system of equations are

x + y = 22

x + 1.5y = 30

Step-by-step explanation:

Let x represent the number of math problems that Olivia solved.

Let y represent the number of pages that Olivia read.

Olivia completed a total of 22 math problems and pages of reading. This means that

x + y = 22- - - - - - - - - - - - - - -1

Olivia can solve each math problem in 1 minute and she can read each page in 1.5 minutes. Olivia completed a total of 22 math problems and pages of reading in 30 minutes. This means that

x + 1.5y = 30 - -- - - - - - - - - -2

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2 years ago

Tammy has planted a small, young tree in her yard. To allow for the tree’s growth, she needs 15 feet in all directions around th

astraxan [27]

Answer:

First, remember that a circle of radius R centered in the point (a, b) can be written as:

(x - a)^2 + (y - b)^2 = R^2

Suppose that we can model the yard as a rectangular coordinate axis.

And the tree is planted in the point (a, b)

If we want to have 15 feet in all directions around the base of the tree (15 ft around the point (a, b))

The section that must remain unplanted is:

(x - a)^2 + (y - b)^2 ≤ R^2

Where the ≤ symbol is used because all the interior of the circle must remain unplanted (border included)

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2 years ago

The​ homoskedasticity-only F​-statistic and the​ heteroskedasticity-robust F​-statistic typically​ are:

The homoskedasticity-only F-statistic and the heteroskedasticity-robust F-statistic typically are: