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lesya692 [45]
2 years ago
14

Tammy has planted a small, young tree in her yard. To allow for the tree’s growth, she needs 15 feet in all directions around th

e base of the tree to remain open and unplanted. Which best describes the section of ground surrounding the base of the tree that should remain unplanted?
Mathematics
1 answer:
astraxan [27]2 years ago
7 0

Answer:

First, remember that a circle of radius R centered in the point (a, b) can be written as:

(x - a)^2 + (y - b)^2  = R^2

Suppose that we can model the yard as a rectangular coordinate axis.

And the tree is planted in the point (a, b)

If we want to have 15 feet in all directions around the base of the tree (15 ft around the point (a, b))

The section that must remain unplanted is:

(x - a)^2 + (y - b)^2   ≤ R^2

Where the ≤ symbol is used because all the interior of the circle must remain unplanted (border included)

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Which test point holds true for y − 2x ≤ 1?
CaHeK987 [17]
So in order to find the correct answer, we can just easily plug in the values to check which ordered pair matches the given inequality above. So based on my solutions, the correct answer would be the last pair. 
<span> y − 2x ≤ 1
0 - 2(5)</span> ≤ 1
0-10  ≤ 1
-10  ≤ 1
Hope this answer helps.
3 0
2 years ago
Angela has the following coins in her pocket:
GaryK [48]

Answer:

  • There are 10 different combinations

  • The list of different combinations is:

        (10p, 1p), (10p, 50p), (10p, 2p), (10p, 20p), (1p, 50p), (1p, 2p),

        (1p, 20p), (50p, 2p), (50p, 20p), (2p, 20p)

Explanation:

The possible combinations are:

1. Assuming the first coin is 10p:

  • (10p, 1p)
  • (10p, 50p)
  • (10p, 2p)
  • (10p, 20p)

2. Asuming the first coin is 1p

Do not count (1p, 10p) as it is the same combination as (10p, 1p)

  • (1p, 50p)
  • (1p, 2p)
  • (1p, 20p)

3. Assuming the first coin is 50p:

Do not count (50p, 10p) nor (50p, 1p) as they are the same combinations (10p, 50p) and (1p, 50p) counted earlier:

  • (50p, 2p)
  • (50p, 20p)

4. Assuming the first coin is 2p:

The only new combination is:

  • (2p, 20p)

5. All the combinations with 20p have already been listed.

Therefore:

  • There are 4 + 3 + 2 + 1 = 10 different combinations

  • The list of different combinations is:

        (10p, 1p), (10p, 50p), (10p, 2p), (10p, 20p), (1p, 50p), (1p, 2p),

        (1p, 20p), (50p, 2p), (50p, 20p), (2p, 20p)

7 0
2 years ago
Mackenzie has a loyalty card good for a 20% discount at her local hardware store. What would her total in dollars and cents be,
8_murik_8 [283]

Answer: $14.0

Step-by-step explanation:

For us to calculate this question, we have to find 20% of $17.45 and then subtract the value gotten from $17.45. This will be:

= $17.45 - (20% × $17.45)

= $17.45 - (0.2 × $17.45)

= $17.45 - $3.49

= $13.96

= $14.0 to nearest cent

6 0
2 years ago
Read 2 more answers
Find the area of quadrilateral ABCD. Round the area to the nearest whole number, if necessary. A(-5, 4) 4 B(0, 3) 2. F(-2, 1) -2
valentina_108 [34]

Answer:26

Step-by-step explanation:

5 0
2 years ago
injured runners train on a special track at a rehabilitation center. The track is a square with a half circle on its left and ri
diamong [38]

Answer:

The length of the track is approximately 51.7 ft

The track has <u>three</u> sides of the square and the distance round <u>a half of a</u> complete circle

Step-by-step explanation:

The given track shape and measurements are;

The shape on the left side of the track  = Square

The shape on the right side of the track  = Half circle

The area of the square on the the left side of the track  = 128 square feet

Therefore, from the area, A, of a square of side length, s, which is s × s, and letting the side length of the square = s, we have;

Area of the square portion of the track = s × s = s² = 128 ft²

Therefore, s = √(128 ft²) = 8·√(2) ft.

Whereby the side length of the square is bounded by the diameter of the half circle, we have;

Length of the diameter of the half circle = s = 8·√(2) ft.

The length of the perimeter of the half circle = π·D/2 = π × 8·√(2)/2 = π × 4·√(2) ≈ 17.77 ft.

The perimeter of the track, which is the length of the track is made up of the three sides of the square opposite to the half circle and the circumference of the half circle.

Therefore;

The length of the track = 3 × 8·√(2) ft + π × 4·√(2) ft. = 4·√2×(π+6) ≈ 51.7 ft

The length of the track ≈ 51.7 ft

Which gives;

The track has <u>three</u> sides of the square and the distance round <u>a half of a</u> complete circle.

5 0
2 years ago
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