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77julia77 [94]
2 years ago
10

A bag holds 26 tiles, each marked with a different letter. What is the probability that one tile chosen at random is not a vowel

?
Mathematics
2 answers:
Alisiya [41]2 years ago
6 0

Answer:

21/26

Step-by-step explanation:

There are 5 vowels in the  26 letters of the alphabet.

So the total of non-vowels = 26-5 = 21.

Therefore the probability of getting  a non vowel = 21/26

grandymaker [24]2 years ago
5 0

Answer:

21/26 percent chance and if you count Y as a vowel 20/26


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Which expression is modeled by this arrangement of tiles?
Gnoma [55]

Answer:

The answer is 16 ÷ 2 = 8.

Step-by-step explanation:

Now, to find the expression modeled by arrangement of tiles.

So, according to the model in the question.

There are 16 tiles in the model.

So, arrangement of 16 tiles divided into 2 groups.

Where each group consist 8 tiles.

So, we can write as:

16\div 2

As 16 is the number of tiles and 2 is the number of groups.

Now, we can check the expression by doing the division.

16\div 2 = 8

Therefore, each group has 8 tiles.

6 0
2 years ago
Read 2 more answers
Round 645 to the nearest ten
Elena L [17]

645 rounded to the nearest 10 is 650, as 5 in the ones place rounds up.
6 0
2 years ago
The owner of a candy store wants to mix some peanuts worth $3 per pound, some cashews worth $10 per pound, and some Brazil nuts
elena-14-01-66 [18.8K]
Let
x = pounds of peanuts
y = pounds of cashews
z = pounds of Brazil nuts.

The total pounds is 50, therefore
x + y + z = 50                   (1)

The total cost is $6.60 per pound for 50 pounds of mixture.
The total is equal to the sum of the costs of the different nuts.
Because the cost for peanuts, cashews, and Brazil nuts are $3, $10, and $9 respectively, therefore
3x + 10y + 9z = 50*6.8
3x + 10y + 9z = 340         (2)

There are 10 fewer pounds of cashews than peanuts, therefore
x = y + 10                         (3)

Substitute (3) into (1) and (2).
y + 10 + y + z = 50
2y + z = 40                     (4)
3(y + 10) + 10y + 9z = 340
13y + 9z = 310                (5)

From (4),
z = 40 - 2y          (6)
Substitute (6) into (5).
13y + 9(40 - 2y) = 310
-5y = -50
y = 10
z = 40 - 2y = 40 - 20 = 20
x = y + 10 = 20

Answer:
Peanuts:     20 pounds
Cashews:   10 pounds
Brazil nuts: 20 pounds


8 0
1 year ago
Which statements are true about the reflectional symmetry of a regular heptagon? Check all that apply. It has only 1 line of ref
Sav [38]

The answer is:

1- A line of symmetry will connect a vertex and a midpoint of an opposite side.

2- It has 7-fold symmetry.

The explanation for this answer is shown below:

1- By definition, a line of symmetry is an imaginary line that divides a figure into two equal images or equal halves. If you connect a vertex and a midpoint of an opposite side of an heptagon by drawing a line, you will obtain two equal halves.

2- An heptagon has seven vertices, therefore, based on the information mentioned above, it has 7-fold symmetry.

8 0
1 year ago
Read 2 more answers
Problem 5 (4+4+4=12) We roll two fair 6-sided dice. Each one of the 36 possible outcomes is assumed to be equally likely. 1) Fin
tekilochka [14]

Answer:

1

p(b) =  \frac{1}{6}

2

p(k) =  \frac{1}{3}

3

P(a) =  \frac{1}{3}

Step-by-step explanation:

Generally when two fair 6-sided dice is rolled the doubles are

(1 1) , ( 2 2) , (3 3) , (4 4) , ( 5 5 ), (6 6)

The total outcome of doubles is N = 6

The total outcome of the rolling the two fair 6-sided dice is

n = 36

Generally the probability that doubles (i.e., having an equal number on the two dice) were rolled is mathematically evaluated as

p(b) =  \frac{N}{n}

p(b) =  \frac{6}{36}

p(b) =  \frac{1}{6}

Generally when two fair 6-sided dice is rolled the outcome whose sum is 4 or less is

(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1)

Looking at this outcome we see that there are two doubles present

So

The conditional probability that doubles were rolled is mathematically represented as

p(k) =  \frac{2}{6}

p(k) =  \frac{1}{3}

Generally when two fair 6-sided dice is rolled the number of outcomes that would land on different numbers is L = 30

And the number of outcomes that at least one die is a 1 is W = 10

So

The conditional probability that at least one die is a 1 is mathematically represented as

P(a) =  \frac{W}{L}

=> P(a) =  \frac{10}{30}

=> P(a) =  \frac{1}{3}

3 0
1 year ago
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