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Vesna [10]
2 years ago
15

Least to greatest -4.3, -82.5, -41 4/5, -13 1/8

Mathematics
1 answer:
kicyunya [14]2 years ago
5 0

-82.5, -41 4/5, -13 1/8, -4.3

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A total of d dollars was donated to 4 charities. Each charity received $375. Which equation can be solved to find the total amou
lidiya [134]

Answer:

If each charity has received $375 and there is 4 charities, the equation should look like this...

$375 x 4 = d

If you are looking how much was donated all together, the answer is:

$1500 dollars in total was donated.

6 0
2 years ago
Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar. David invested $220
S_A_V [24]

Answer:

The answer is 23 years.

Step-by-step explanation:

We will use the formula :

A=P(1+r)^{t}

Here P = 220

r = 3%

A = 400

Putting these values in the formula we get,

400=200(1+0.03)^{t}

2=1.03^{t}

Taking log on both sides,

ln(1.03)t=ln 2

t=\frac{ln(2)}{ln(1.03)}

t=23.44 or rounding to nearest, t=23 years

The graph of the function can be shown as below.

3 0
2 years ago
Read 2 more answers
"Consider the probability distribution of X, where X is the number of job applications completed by a college senior through the
Citrus2011 [14]

Answer:

Option b

Step-by-step explanation:

Given that the probability distribution of X, where X is the number of job applications completed by a college senior through the school’s career center.

 Expected observed Diff

x p(x) p(x)*1000  

   

0 0.002 2  

1 0.011 11 14 -3

2 0.115 115 15 100

3 0.123 123 130 -7

4 0.144 144  

5 0.189 189  

6 0.238 238  

7 0.178 178  

   

1 1000

We find that there is a large difference in 2 job application

Hence option b is right.  

4 0
1 year ago
Announcements for 84 upcoming engineering conferences were randomly picked from a stack of IEEE Spectrum magazines. The mean len
Marina86 [1]

Answer:

Step-by-step explanation:

Hello!

You need to construct a 95% CI for the population mean of the length of engineering conferences.

The variable has a normal distribution.

The information given is:

n= 84

x[bar]= 3.94

δ= 1.28

The formula for the Confidence interval is:

x[bar]±Z_{1-\alpha/2}*(δ/n)

Lower bound(Lb): 3.698

Upper bound(Ub): 4.182

Error bound: (Ub - Lb)/2 = (4.182-3.698)/2 = 0.242

I hope it helps!

6 0
2 years ago
An investment of $500 increases at a rate of 12.5% per year. What is the value of the investment after 30 years? Round to the ne
NemiM [27]
Here's the equation:
0.125(500) + 500
But because it is 30 years:
30(0.125(500)) + 500
3.75(500) + 500
We can make it simpler:
4.75(500)
2375
You will have $2375
7 0
2 years ago
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