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Gemiola [76]
2 years ago
13

The number of people using an older version of a spreadsheet program decreases at a rate that is proportional at any time to the

number of people still using the version at that time.
There were 10{,}00010,00010, comma, 000 people using the older version of the spreadsheet program when the new version first came out. The number of people still using the older version decreases by 20\%20%20, percent every 666 months.
Mathematics
1 answer:
mario62 [17]2 years ago
6 0

Answer:

The decrease in the use of older version is given by,y = 10000 \cdot0.60^{t}.

Step-by-step explanation:

It is provided that the number of people using an older version of a spreadsheet program decreases at a rate that is proportional at any time to the number of people still using the version at that time.

The exponential decay function is given as follows:

y=a(1-r)^{t}

Here,

<em>y</em> = final value

<em>a</em> = initial value

<em>r</em> = decay rate

<em>t</em> = time taken

It is provided that there were 10,000 people using the older version of the spreadsheet program when the new version first came out. And the number of people still using the older version decreases by 20% every 6 months.

So, every half-yearly the decrease in the number of people using the older version is 20%. This implies for a year the decay rate is 40%.

Then the decrease in the use of older version is given as follows:

y=10000(1-0.40)^{t}\\\\y=10000\cdot 0.60^{t}

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The aquarium at Sea Critters Depot contains 140 fish. Eighty of these fish are green swordtails (44 female and 36 male) and 60 a
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Given that:

Total number of fish = 140

Fish are green swordtails female = 44

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Solution:

A. We have to find the probability that the selected fish is a green swordtail.

\text{P(green swordtail)}=\dfrac{\text{Total green swordtail fish}}{\text{Total fish}}

\text{P(green swordtail)}=\dfrac{80}{140}

\text{P(green swordtail)}=\dfrac{4}{7}

Therefore, the probability that the selected fish is a green swordtail is \dfrac{4}{7}.

B.  We have to find the probability that the selected fish is male.

\text{P(Male fish)}=\dfrac{\text{Total male fish}}{\text{Total fish}}

\text{P(Male fish)}=\dfrac{36+24}{140}

\text{P(Male fish)}=\dfrac{60}{140}

\text{P(Male fish)}=\dfrac{3}{7}

Therefore, the probability that the selected fish is a male, is \dfrac{3}{7}.

C. We have to find the probability that the selected fish is a male green swordtail.

\text{P(Male green swordtail)}=\dfrac{\text{Total male green swordtail fish}}{\text{Total fish}}

\text{P(Male green swordtail)}=\dfrac{36}{140}

\text{P(Male green swordtail)}=\dfrac{9}{35}

Therefore, probability that the selected fish is a male green swordtail is \dfrac{9}{35}.

D.

We have to find the probability that the selected fish is either a male or a green swordtail.

\text{P(Male or green swordtail)}=\dfrac{\text{Total male or green swordtail fish}}{\text{Total fish}}

\text{P(Male or green swordtail)}=\dfrac{44+36+24}{140}

\text{P(Male or green swordtail)}=\dfrac{96}{140}

\text{P(Male or green swordtail)}=\dfrac{24}{35}

Therefore, the probability the selected fish is either a male or a green swordtail is \dfrac{24}{35}.

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Sholpan [36]

Answer:

<em>Hi There!</em>

Answer:

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Because, Arjun takes quantity of chocolate = 20 mL

<em><u>Choice 1.</u></em>

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<em>Good Luck!</em>

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