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2 years ago

If AD=20 and AC=3x+4, find the value of x. Then find AC and DC. I don't understand.

Mathematics

1 answer:

Fofino [41]2 years ago

5 0

<span>Using the information we have 3x+4=40 Do the same to each side of the equation to eliminate for x. 3x+4=40 Minus 4 from each side 3x=40-4 3x=36 Divide 3 from each side x=36/3 x=12 AC=3x+4 insert the value of x 3(12)+4=40 AC=40 AD=20</span>

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Consider f(x) = 1.8x – 10 and g(x) = −4. A 2 column table with 6 rows. The first column, x, has the entries, negative 4, 0, 2, 4

viktelen [127]

Answer:1.8x – 10 = –4; x = 1.8 x minus 10 equals negative 4; x equals StartFraction 10 Over 2 EndFraction.

1.8 - 10= -4 x= -10/9

Step-by-step explanation:

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A bowl of flower seeds contains 5 petunia seeds and 15 begonia seeds. Riley calculated the probability that a random selected se

Vlad1618 [11]

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2 years ago

Which statements about the factors of the terms in the expression 20 a + 15 a b + 24 b are true? Select three options.

ExtremeBDS [4]

Answer:

Following are the true statements

2. The factors common to 20a and 15ab are 1, 5, and a.

3. The factors common to 20a and 24b are 1, 2, and 4.

5. The GCF of the expression is 1

Step-by-step explanation:

Expression is 20a + 15ab + 24b

Now lets have a look at each of the options provided!

1. The factors common to 20a and 15ab are 1, 5, a, and b.

False

As you can see there is no b in 20a term only 1,5,a are common hence it is false.

2. The factors common to 20a and 15ab are 1, 5, and a.

True

The terms 20a and 15ab are divisible by 1,5,a hence it is true.

3. The factors common to 20a and 24b are 1, 2, and 4.

True

The terms 20a and 24b are divisible by 1,2,4 hence it is true

4. The GCF of the expression is ab.

False

20a + 15ab + 24b

As you can see ab is not common in all of the terms hence it cannot be greatest common factor

5. The GCF of the expression is 1

True

Factor of 20 are: 2,2,5,1

Factor of 15 are: 3,5,1

Factor of 24 are: 2,2,2,3,1

As you can see the only common factor among all the terms is 1 hence GCF is 1.

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2 years ago

Suppose a research paper states that the distribution of the daily sea-ice advance/retreat from each sensor is similar and is ap

strojnjashka [21]

Answer:

The value of the parameter is λ is 0.03692

Step-by-step explanation:

Consider the provided function.

$f(x) = 0.5\lambda e^{-\lambda |x|}$ for −∞ < x < ∞.

It is given that standard deviation is given as 38.3 km.

Now we need to calculate the value of parameter λ.

The general formula for the probability density function of the double exponential distribution is: $f(x)=\frac{e^{-|\frac{x-\mu}{\beta}|}}{2\beta}$

Where μ is the location parameter and β is the scale parameter.

Compare the provided equation with the above formula we get.

$\lambda=\frac{1}{\beta}$ and μ = 0.

Standard deviation = √2β

$S.D=\sqrt{2} \beta\\\beta=\frac{38.3}{\sqrt{2}}\\\beta=27.08219$

Now substitute the value of β in $\lambda=\frac{1}{\beta}$ .

$\lambda=\frac{1}{27.08219}=0.03692$

Hence, the value of the parameter is λ is 0.03692

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2 years ago