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2 years ago

13

A school baseball team raised $810 for new uniforms. each player on the team sold one book of tickets. there were 10 tickets in

a book and each ticket cost $3.what equation can you write and solve to find the cost of each book of tickets sold?

1 answer:

Ilia_Sergeevich [38]2 years ago

8 0

3 x 10 = cost of each book of tickets sold

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A direct variation function contains the points (–9, –3) and (–12, –4). Which equation represents the function? y = –3x y = –y e

atroni [7]

Answer:

The equation which represents the function is given by,

x = 3y .

Step-by-step explanation:

The direct variation function contains the points, (-9, -3) and (-12, -4).

Here,

$\frac {-9}{-3} = \frac {-12}{-4}$ = 3

So, the equation which represents the function is given by,

x = 3y .

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1. Which expression calculates the speed in meters per second of an object that travels a distance of 100 m every 20 s?

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1. 100 * 20
2. 7 hours
3. 141 kilometers
4. 8.5 hours
5. 55.75 mi/h

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Solve the system of equations. -9Y +4X -20 =0<br> -7Y +16 X -80 =0<br> X=<br> Y=

Fofino [41]

Answer:

X=5, Y=0

Step-by-step explanation:

-9Y +4X -20=0

-7Y+16X-80=0

1. We can multiply the first equation by 4. This will equal to -36Y +16X-80=0.

-36Y +16X -80 =0

-7Y+16X-80=0

2. We can subtract these two equations.

-36Y +16X -80 =0

-7Y+16X-80=0

We will get -29Y =0. Y=0.

3. Then we can substitute y into the first equation. -9(0) +4x-20 =0. 4x=20. x=5

X=5, Y=0

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2 years ago

A daylily farm sells a portion of their daylilies and allows a portion to grow and divide. The recursive formula an=1.5(an-1)-10

zaharov [31]

Answer:

Hence, the number of daylilies in the first year were:

600

Step-by-step explanation:

It is given that:

the recursive formula $a_n=1.5(a_{n-1})-100$ represents the number of daylilies, a, after n years.

Also we are given that in the fifth year they have 2,225 daylilies.

i.e.

$a_5=2225$

Also,

$a_5=1.5a_4-100$

$a_4=1.5a_3-100$

This means that:

$a_5=1.5(1.5a_3-100)-100\\\\a_5=(1.5)^2a_3-100\times (1.5)-100$

Similarly,

$a_3=1.5a_2-100$

so,

$a_5=(1.5)^2\times (1.5a_2-100)-100\times (1.5)-100\\\\a_5=(1.5)^3a_2-(1.5)^2\times 100-(1.5)\times 100-100$

and so, putting $a_2$ in terms of $a_1$ we get:

$a_5=(1.5)^4a_1-(1.5)^3\times 100-(1.5)^2\times 100-(1.5)\times 100-100$

Now on putting the value of $a_5$ we find the value of $a_1$

$2225-(1.5)^4a_1-337.5-225-150-100\\\\2225=5.0625a_1-812.5\\\\2225+812.5=5.0625a_1\\\\3037.5=5.0625a_1\\\\a_1=\dfrac{3037.5}{5.0625}\\\\a_1=600$

Hence, the number of daylilies in the first year were:

600

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This is a positive temperature.

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