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Rzqust [24]
2 years ago
7

 A hiker is walking down a mountain. She walked​ 5,978 feet in 17 minutes. In that​ time, she descended​ 1,024 feet from the top

of the mountain. She then walked​ 3,972 feet in 7 minutes. In that​ time, she descended 500 more feet. Express the average rate of change in altitude of the hiker from her starting point to her ending point as a unit rate.
Mathematics
1 answer:
Karo-lina-s [1.5K]2 years ago
5 0
First walk=descend of 1024 feet in 17 minutes
second walk=descend of 500 feet in 7 minutes

so in total she descended 1024+500=1524 feet in 7+17=24 minutes
as an average rate this equals 1524/24=63.5 feet/minute descended
or an average rate of -63.5 feet/minute in altitude (note the minus)
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Given:

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m∠NMK

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By property of circle:

<em>If a tangent and a secant intersect outside a circle, then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs.</em>

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Multiply by 2 on both sides, we get

$\Rightarrow 2\times (2x+45)=2\times \frac{1}{2} (2x + 90)

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$\Rightarrow 4x=2x

Subtract 2x from both sides.

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m∠NMK = 2x + 45

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              = 45

Therefore m∠NMK = 45.

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