Answer: she must complete 4 levels to have a point fewer than 20
Step-by-step explanation:
Given the following :
Starting point = 100 points
Passing a level = - 8 points
Catching a flower = - 3 points
Suppose Tina catches 6 flowers per level
Number of levels she must complete to have fewer Than 20 points
Total number of points lost per level:
Catching 6 flowers = -(6 × 3)
Passing the level = - 8
= - 18 + - 8 = - 26 points
Number of levels she must complete to have < 20
Let number of levels = y
Starting points - (26 × number of levels) < 20
100 - (26y) < 20
100 - 26y < 20
-26y < 20 - 100
-26y < - 80
y > 80/26
y > 3.07
Hence she must complete 4 levels to have a point fewer than 20
<span>The
high school marching band rehearses with either 6 or 10 members in
every line.What is the smallest number of people who can be in the
marching band?
</span>
Answer:
C. Stacy
Step-by-step explanation:
One way to compare is to convert all the fractions into decimals
Rachel works 2/3 of her shift: Approximately= 0.667
Jose works 1/6: approx. = 0.1667
Damon works 4/5= 0.80
Stacy works 6/7: approx. = 0.8571
Now this makes it much easier to compare
And since 0.85714 (Stacy's shift) is the largest number, Stacy has completed the largest portion of her shift
Answer: The correct option is (D) P″(9, -12) and Q″(15, -3).
Step-by-step explanation: Given that triangle PQR is dilated by a scale factor of 1.5 to form triangle P′Q′R′. This triangle is then dilated by a scale factor of 2 to form triangle P″Q″R″.
The co-ordinates of vertices P and Q are (3, -4) and (5, -1) respectively.
We are to find the co-ordinates of the vertices P″ and Q″.
<u>Case I :</u> ΔPQR dilated to ΔP'Q'R'
The co-ordinates of P' and Q' are given by

<u>Case II :</u> ΔP'Q'R' dilated to ΔP''Q''R''
The co-ordinates of P'' and Q'' are given by

Thus, the co-ordinates of the vertices P'' and Q'' are (9, -12) and (15, -3).
Option (D) is CORRECT.
<u></u>
I assume you mean -x^3 + 4x + 3
so what you need is 4x + 3 > x^3
the only whole number it could be is 2 because 2x2x2 +3 > 2x2x2