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Sonbull [250]
2 years ago
10

Della bought a tree seedling that was 2 1/4 feet tall. During the first year, it grew 1 1/6 Feet. After two years, it was 5 feet

tall. How much did the seedling grow during the second year?
Mathematics
1 answer:
Margarita [4]2 years ago
3 0

Answer:

Step-by-step explanation:

Alright, lets get started.

Della bought a tree seeding that was 2\frac{1}{4} feet tall means \frac{9}{4} feet.

First year it grew 1\frac{1}{6} feet means it grew \frac{7}{6} feet.

It means after 1 year, the height of tree will be = \frac{9}{4}+\frac{7}{6}=\frac{41}{12}

After 2 years, the height of tree is = 5 feet

So, it grew in second year = 5-\frac{41}{12}

So, it grew in second year = \frac{60-41}{12}=\frac{19}{12}

So, it grew in second year=1\frac{7}{12} feet.   :  Answer

Hope it will help :)

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Answer: she must complete 4 levels to have a point fewer than 20

Step-by-step explanation:

Given the following :

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Let number of levels = y

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Hence she must complete 4 levels to have a point fewer than 20

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<span>The high school marching band rehearses with either 6 or 10 members in every line.What is the smallest number of people who can be in the marching band? </span>
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One way to compare is to convert all the fractions into decimals

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<u></u>

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I assume you mean -x^3 + 4x + 3 
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