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Crank
2 years ago
10

For a specific species of fish in a pond, a wildlife biologist wants to build a regression equation to predict the weight of a f

ish based on its length. The biologist collects a random sample of this species of fish and finds that the lengths vary from 0.75 to 1.35 inches. The biologist uses the data from the sample to create a single linear regression model. Would it be appropriate to use this model to predict the weight of a fish of this species that is 3 inches long
Mathematics
1 answer:
sashaice [31]2 years ago
3 0

Answer: First of all, we will add the options.

A. Yes, because 3 inches falls above the maximum value of lengths in the sample.

B. Yes, because the regression equation is based on a random sample.

C. Yes, because the association between length and weight is positive.

D. No, because 3 inches falls above the maximum value of lengths in the sample.

E. No, because there may not be any 3-inch fish of this species in the pond.

The correct option is D.

Step-by-step explanation: It would not be appropriate to use the model to predict the weight of species that is 3 inches long because 3 inches falls above the maximum value of lengths in the sample.

As we can see from the question, the model only accounts for species that are within the range of 0.75 to 1.35 inches in length, and species smaller or larger than that length have not been taken into consideration. Therefore the model can not be used to predict the weights of fishes not with the range accounted for.

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Line segment ON is perpendicular to line segment ML, and PN = 10.
Ne4ueva [31]

we know that

Triangle MOL is an isosceles triangle

because

MO=OL=radius\ of\ circle=25\ units

ON=25\ units

ON=OP+PN\\ 25=OP+10\\ OP=25-10\\ OP=15\ units

Find the base MP

Applying the Pythagorean Theorem in the right triangle MPO

MO^{2} =MP^{2}+PO^{2}\\ MP^{2}=MO^{2}-PO^{2}\\ MP^{2}=25^{2}-15^{2}\\ MP^{2}=400\\ MP=20\ units

ML=2*MP\\ ML=2*20\\ ML=40\ units

Find the area of triangle MOL

A=\frac{1}{2}ML*PO\\ \\ A=\frac{1}{2}*40*15\\ \\ A=300\ unit^{2}

therefore

the answer is

the area of triangle MOL is

300 square units

3 0
2 years ago
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Translate triangle a by vector (-3/1)to give triangle b. Then rotate your triangle b 180 degrees around the origin to give trian
Dmitrij [34]

Answer:

Rotation of triangle A across a point (1.5, -0.5) by 180°.

Step-by-step explanation:

Translation of a figure about a vector \binom{-3}{1} means translation of a figure by 3 units to the left on x-axis and 1 unit in the positive direction of the y-axis.

Rule for the translation will be,

(x, y) → [(x - 3), (y + 1)]

From the figure attached,

Vertices of the triangle A are A(1, -1), B(1, -4) and C(3, -4)

After translation new image points will be A'(-2, 0), B'(-2, -3), C'(0, -3).

After rotation of these image points 180° about the origin will be,

Rule for the rotation,

(x, y) → (-x, -y)

A'(-2, 0) → A"(2, 0)

B'(-2, -3) → B"(2, 3)

C'(0, -3) → C"(0, 3)

Therefore, A(1, -1) → A"(2, 0) is the single transformation.

Rule for this transformation which maps triangle C to A will be defined by,

Rotation of triangle A across a point (1.5, -0.5) by 180°.

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2 years ago
Which expression represents "10 subtracted from the quotient of 3 and a number"? a. 3n-10 b. 3/n - 10 (the / is a fraction bar)
kiruha [24]
B. because it is 10 being subtracted from the fraction. 
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2 years ago
An orange is shot up into the air with a catapult. The function h given by h(t)=15+60t-16t^2 models the orange’s height, in feet
Studentka2010 [4]

Complete question is:An orange is shot up into the air with a catapult. The function h given by h(t) = 15 + 60t - 16t² models the orange’s height, in feet, t seconds after it was launched.

Select all the true statements about the situation.

Options:

1. The domain of function h only contains values greater than or equal to 0.

2. The orange is at the same height 1 second after launch and 2 seconds after launch.

3. After 3 seconds, the orange has hit the ground.

4. The orange is 15 feet above the ground when it is launched.

5. The value t = 10 does not belong to the domain of h.

Answer:

Option 1 - True

Option 2 - False

Option 3 - False

Option 4 - True

Option 5 - True

Step-by-step explanation:

Looking at the options,

-The domain is the x or t value and it is time. Now, time can only be positive or greater than or equal to zero i.e. t ≥ 0. Thus, option 1 is true.

- At t = 1 second;

h = 15 + 60(1) - 16(1)²

h = 15 + 60 - 16 = 59 ft

Also, at t = 2 seconds;

h = 15 + 60(2) - 16(2)²

h = 15 + 120 - 64 = 71 ft

So,value of h is not the same at t = 1 and t = 2. Thus, option 2 is not true.

- The orange will hit the ground when h(t) = 0.

However, at t = 3;

h(t) = 15 + 60(3) - 16(3)²

h(t) = 51 ft

h(t) is not equal to zero at t = 3, so option 3 is false

- when the orange is launched it is at time t = 0.

Thus,

h(0) = 15 + 60(0) - 16(0)²

h(0) = 15 ft

So option 4 is true.

- At t=10, h(t) = 15 + 60(10) - 16(10)²

h(10) = -985

This means the orange would be below ground level and thus doesn't belong to the domain of h, so option 5 is true.

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