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musickatia [10]
1 year ago
8

If x+y=3 , x²+y²=5 then xy is what

Mathematics
1 answer:
tigry1 [53]1 year ago
6 0
Xy is (1,2) because 1+2=3 and 1^2+2^2=5 therefor ur answer is xy= (1,2)
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THE COST OF SALAD AT A RESTAURANT DEPENDS ON MANY FACTORS LIST AT LEAST TWO INDEPENDENT VARIABLES THAT COULD AFFECT THE COST OD
Contact [7]

Answer:

A

Step-by-step explanation:

7 0
2 years ago
What is the quotient of -8a^8b^-2/ 10a^-4b^-10 in simplified form?
postnew [5]

Here are a few rules with exponents that you need to know:

  1. Dividing exponents of the same base: \frac{x^m}{x^n}=x^{m-n}

For this, divide:

\frac{-8a^8b^{-2}}{10a^{-4}b^{-10}}=\frac{-8}{10}a^{8-(-4)}b^{-2-(-10)}=-\frac{4}{5}a^{12}b^8

<u>Your final answer is -\frac{4}{5}a^{12}b^8</u>

7 0
2 years ago
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Byron has 1 7/10 kilograms of black pepper. He uses 7/8 of the black pepper and splits between 7 pepper shakers. How much pepper
IrinaVladis [17]
Amount of black pepper = 1 7/10 kg = 17/10 kg.
Amount used is
(7/8)*(17/10) = 119/80 kg

This amount is split between 7 shakers. Each shaker has
(119/80)/7 = 17/80 kg = 0.2125 kg

Answer: 17/80 kg (or  0.2125 kg)
4 0
1 year ago
Evaluate the triple integral ∭ExydV where E is the solid tetrahedon with vertices (0,0,0),(5,0,0),(0,9,0),(0,0,4).
Elan Coil [88]

Answer: \int\limits^a_E {\int\limits^a_E {\int\limits^a_E {xy} } \, dV = 1087.5

Step-by-step explanation: To evaluate the triple integral, first an equation of a plane is needed, since the tetrahedon is a geometric form that occupies a 3 dimensional plane. The region of the integral is in the attachment.

An equation of a plane is found with a point and a normal vector. <u>Normal</u> <u>vector</u> is a perpendicular vector on the plane.

Given the points, determine the vectors:

P = (5,0,0); Q = (0,9,0); R = (0,0,4)

vector PQ = (5,0,0) - (0,9,0) = (5,-9,0)

vector QR = (0,9,0) - (0,0,4) = (0,9,-4)

Knowing that cross product of two vectors will be perpendicular to these vectors, you can use the cross product as normal vector:

n = PQ × QR = \left[\begin{array}{ccc}i&j&k\\5&-9&0\\0&9&-4\end{array}\right]\left[\begin{array}{ccc}i&j\\5&-9\\0&9\end{array}\right]

n = 36i + 0j + 45k - (0k + 0i - 20j)

n = 36i + 20j + 45k

Equation of a plane is generally given by:

a(x-x_{0}) + b(y-y_{0}) + c(z-z_{0}) = 0

Then, replacing with point P and normal vector n:

36(x-5) + 20(y-0) + 45(z-0) = 0

The equation is: 36x + 20y + 45z - 180 = 0

Second, in evaluating the triple integral, set limits:

In terms of z:

z = \frac{180-36x-20y}{45}

When z = 0:

y = 9 + \frac{-9x}{5}

When z=0 and y=0:

x = 5

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\int\limits^5_0 {\int\limits {\int\ {xy} \, dz } \, dy } \, dx

Calculating:

\int\limits^5_0 {\int\limits {\int\ {xyz}  \, dy } \, dx

\int\limits^5_0 {\int\limits {\int\ {xy(\frac{180-36x-20y}{45} - 0 )}  \, dy } \, dx

\frac{1}{45} \int\limits^5_0 {\int\ {180xy-36x^{2}y-20xy^{2}}  \, dy } \, dx

\frac{1}{45} \int\limits^5_0  {90xy^{2}-18x^{2}y^{2}-\frac{20}{3} xy^{3} } \, dx

\frac{1}{45} \int\limits^5_0  {2430x-1458x^{2}+\frac{94770}{125} x^{3}-\frac{23490}{375}x^{4}  } \, dx

\frac{1}{45} [30375-60750+118462.5-39150]

\int\limits^5_0 {\int\limits {\int\ {xyz}  \, dy } \, dx = 1087.5

<u>The volume of the tetrahedon is 1087.5 cubic units.</u>

3 0
2 years ago
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Virty [35]
The answer is 224.7 you got to turn 30% into decimal which is 0.30 
then multiply 0.30 and 749 which equals 224.7

6 0
2 years ago
Read 2 more answers
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