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Anna71 [15]
2 years ago
13

A service club is organizing a concert to raise funds for a retirement home. The club determines that the revenue from the conce

rt can
be represented by R(x) = 0.0027x3 - 125, where x is the number of tickets sold. The cost to put on the concert is represented by the
function C(X) = 21x + 11,305.
Which of the following functions describes the funds raised, F(x), as a function of the number of tickets sold?
FX) = 0.0027x3 - 21x - 11,430
FAX) = 0.0027x3 + 21x - 11,180
FX) = 0.0027x3 - 21x - 11,180
F(X) = 0.0027x3+
+ 21-11,430

Mathematics
2 answers:
irina1246 [14]2 years ago
7 0

Answer:

maybe is a

Step-by-step explanation:

valentina_108 [34]2 years ago
5 0

Answer:

F(x) = 0.0027x^3 - 21X - 11,430

Step-by-step explanation:

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Which of the following terms correctly describe the object below. Check all that apply
mars1129 [50]

Answer:

Option a,d and e are correct.

Step-by-step explanation:

Pyramid is  the figure in which every base and apex forms triangle.

Polygon is two dimensional figure with straight lines.

Square is a figure in which all four sides are equal.

Solid is a three dimensional figure.

Polyhedron is a three dimensional figure with straight edges and sharp corners.

Prism is a polyhedron with parallel bases.

The given figure is:

Pyramid

Solid

Polyhedron


4 0
2 years ago
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The parent function f(x) = x3 is transformed to g(x) = (x – 1)3 + 4. Identify the graph of g(x).
Dominik [7]

we have f(x)=x^3 which is a cubic function.

and =(x-1)^3+4.

from f(x) and g(x) we know that both are cubic and g(x) has shrink of 1 and up by 4 units in x axis .

4 0
2 years ago
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David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below.
Vikentia [17]

Answer:

Given Polynomial:

80b^4-32b^2c^3+48b^4c

Factors of Coefficient of terms

80 = 5 × 16

32 = 2 × 16

48 = 3 × 16

Common factor of the coefficient of all term is 16.

Each term contain variable. So the Minimum power of b is common from all terms.

Common from all variable part comes b².

So, Common factor of the polynomial = 16b²

⇒ 16b² ( 5b² ) - 16b² ( 2c³ ) + 16b² ( 3b²c )

⇒ 16b² ( 5b² - 2c³ + 3b²c )

Therefore, Statements that are true about David's word are:

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

In step 6, David applied the distributive property

8 0
2 years ago
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How many pounds of water must be evaporated from 50 pounds of a 3% salt solution so that the the remaining solution will be 5 %
svlad2 [7]

Answer:

Step-by-step explanation:

This is kinda tricky, but not nearly as bad as d = rt problems. Those are a nightmare!

We will make a table for this:

                         #lbs solution           *          % salt         =           lbs. salt

  3% solution

-  <u>Water                                                                                                      </u>

New solution

And we will now fill in what we know. The 3% solution part is easy. The number of pounds of that is 50 and the percent salt in 3% salt is....well, 3%. As a decimal, it is .03:

                             #lbs solution        *        %salt        =        lbs salt

  3% solution                50                 *          .03         =           1.5

-  <u>Water                                                                                                 </u>

New solution

The last column there with a 1.5 in it is the product of 50 times .03, since that is what the formula at the top of the table tells us we have to use. Now for the water. That's easy, too, since the amount of water we are evaporating (notice the subtraction sign out front of the word "water"; that indicates we are removing water) is our unknown, and we also know that water has 0% salt in it:

                          #lbs solution         *       %salt        =        lbs. salt

   3% solution            50                  *         .03         =           1.5

-   <u>Water                       x                  *            0          =            0         </u>

New solution

Now all we have left is the new solution row and the equation. Finding the equation from a mixture table is as easy as it can be! Super easy!

The new solution will be 50 - x since, going down column 1, we are subtracting the water from the 3% solution, the % salt is to be 5%:

                            #lbs. solution        *       %salt        =        lbs. salt

   3% solution               50                *         .03          =           1.5

-   <u>Water                          x                 *           0           =            0         </u>

New solution         50 - x                  *         .05          =     2.5 - .05x

Now we're ready for our equation. I got the 2.5 - .05x from multiplying

.05(50 - x), just so you know.

if we had to subtract the water from the salt solution and set it equal to the new solution in the first column, we also have to do it in the third column:

1.5 - 0 = 2.5 - .05x and solve for x:

-1 = -.05x so

x = 20 pounds of water

4 0
2 years ago
One way to solve the system is to _____________ a variable.
Ivahew [28]

One way to solve the system is to <u>substitute</u> a variable.

<u>Explanation:</u>

One approach to solve an equation is by substitution of one variable. Right now, a condition for one factor, at that point substitute that arrangement in the other condition, and explain. All value(s) of the variable(s) that fulfills a condition, disparity, arrangement of conditions, or arrangement of imbalances.

The technique for tackling "by substitution" works by settling one of the conditions (you pick which one) for one of the factors (you pick which one), and afterward stopping this go into the other condition, "subbing" for the picked variable and fathoming for the other. At that point you back-explain for the principal variable.

8 0
2 years ago
Read 2 more answers
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