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Nady [450]
2 years ago
6

Determine the input value for which the statement f(x) = g(x) is true. From the graph, the input value is approximately_______ .

f(x) = 3 and g(x) = x – 2 3 = x – 2 5 = x The x-value at which the two functions’ values are equal is______ .

Mathematics
2 answers:
gavmur [86]2 years ago
7 0

Answer:

From the graph, the input value is approximately

3.5

The x-value at which the two functions’ values are equal is

10/3

Step-by-step explanation:

Julli [10]2 years ago
6 0

In this question , we have a graph given, and we have to find the x coordinate of the intersection point .

From the graph , the input value is approximately 3.3 .

In the graph,

f(x) =3

And for g(x), we need the slope and y intercept .

Slope is the ratio of rise and run .

Here rise equals 3 units and run equals 2 units. And the graph touch the y axis at -2 .

So the equation of g(x) is

g(x) = \frac{3}{2}x -2

We need to do

f(x)= g(x)

Substituting the values of the two functions, we will get

3 = \frac{3}{2}x -2

Adding 2 to both sides

5 = \frac{3}{2}x

Cross multiplication

10 =3x
\\
x = \frac{10}{3}

x = 3.3

So the input value is 3.3 approx


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A machine shop produces heavy duty high endurance 20-inch rods that are meant for use in a variety of military grade equipment.
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The probability that a defective rod can be salvaged = 0.50

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4 0
2 years ago
If the farmer has 234 feet of fencing, what are the dimensions of the region which enclose the maximal area?
marissa [1.9K]

Answer: 58 ft × 58 ft  

Step-by-step explanation:

Let the length of the region = x feet

And, the width of the region = y feet

Since, the perimeter of the region = 234 feet ( Given )

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⇒ x+y = 117

⇒ y = 117 - x

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By differentiating the above equation with respect to x,

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Again differentiating equation A'(x) with respect to x,

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⇒ For x = 58.5 feet the area A(x) is maximum,

⇒ The length of the region having maximum area = x = 58.5 feet

And, the width of the region having maximum area = y = 117-x= 117 - 58.5=58.5 feet,

⇒ The dimension of the region having the maximum area = 58.5 ft × 58.5 ft

8 0
2 years ago
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