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Morgarella [4.7K]
2 years ago
15

549 vehicles on 9 acres

Mathematics
2 answers:
lyudmila [28]2 years ago
7 0

Answer:

61 per acre

Step-by-step explanation:

im smart

cupoosta [38]2 years ago
3 0
The answer is 549 divided by 9 = 61 vehicles per acre
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Suppose that a high school marching band has 125 members. Of these 125 band members, 41 are seniors, 24 play the trumpet, and 10
Alborosie

Answer:

<em>The probability is 42%</em>

Step-by-step explanation:

<u>Conditional Probability</u>

It's the probability of the occurrence of an event B knowing that an event A has already occurred and A and B are related (not independent).

If P(A) is the probability of occurrence of A, P(A\cap B) is the probability of both events to occur, and P(B|A) is the required probability occurrence of B:

\displaystyle P(B|A)=\frac{P(A\cap B)}{P(A)}

We know a high school marching band has 125 members, from which 41 are seniors (event B), 24 play the trumpet (event A), and 10 are seniors who play the trumpet.

The probability that a randomly selected band member plays the trumpet is

\displaystyle P(A)=\frac{24}{125}

The probability that he or she has both attributes is

\displaystyle P(A\cap B)=\frac{10}{125}

Thus, the required conditional probability is

\displaystyle P(B|A)=\frac{\frac{10}{125}}{\frac{24}{125}}

\displaystyle P(B|A)=\frac{10}{24}=\frac{5}{12}=0.42

The probability is 42%

5 0
2 years ago
A. imagine that you are one of the people who left the luncheon with a contagious disease and interacted with an average of 9 di
shusha [124]

1.       In line with the test each person who came into interaction with the infected person will become infected also. With this information, the calculation would be: 9 people each day for 7days would be equivalent to 9 x 7 which equals 63 people.

2.       Here were 7 other people in the experiment if patient zero is left out. If each person intermingled with 6 different people every day in 7 days then the calculation would be: 7 people infected x 6 new people = 42 infected people each day

42 new people every day x 7 days = 294 infected persons.

8 0
2 years ago
You save $5,000.00 and invest 60% of it in stocks while leaving the rest in a savings account earning a 4.9% APR. The stock incr
Angelina_Jolie [31]

Answer:

5,340

Step-by-step explanation:

Hi there:)

Amount invested in stock

=5000×0.6=3000

Amount invested in a saving account

5000-3000=2000


The stock increases 9% in the first year

3,000×(1+0.09)=3,270

and loses 4% of its value the second year

3,270×(1−0.04)=3,139.2

Amount of a saving account after two years

2,000×(1+0.049)^(2)=2,200.8


the total amount gained during the 2 years

3,139.2+2,200.8=5,340...answer


Hope it helps




8 0
2 years ago
Read 2 more answers
How do I solve w(x)=4x 5; find w(-8)?
Andrei [34K]
Plug -8 in for x: 4(-8) + 5 solve: -32 + 5 -27
4 0
2 years ago
4. Hydrocarbons in the cab of an automobile were measured during trips on the New Jersey Turnpike and trips through the Lincoln
pochemuha

Answer:

No these these result do not differ at 95% confidence level  

Step-by-step explanation:

From the question we are told that

  The first concentrations is  c _1= 30.0 \ g/m^3

      The second concentrations is  c _2 = 52.9 \ g/m^3

  The first sample size is  n_1 =  32

    The second sample size is  n_2 =  32

   The  first standard deviation is \sigma_1 =  30.0

     The  first standard deviation is \sigma_1 =  29.0

The mean for  Turnpike is  \= x _1 = \frac{c_1}{n}  =  \frac{31.4}{32} = 0.98125

The mean for   Tunnel is  \= x _2 = \frac{c_2}{n}  =  \frac{52.9}{32} = 1.6531

The  null hypothesis is  H_o  :  \mu _1 - \mu_2  =  0

The  alternative hypothesis is  H_a  :  \mu _1 - \mu_2  \ne  0

Generally the test statistics is mathematically represented as

              t =  \frac{\= x_1 - \= x_2}{ \sqrt{\frac{\sigma_1^2}{n_1}  +\frac{\sigma_2^2}{n_2} }}

         t =  \frac{0.98125 - 1.6531}{ \sqrt{\frac{30^2}{32}  +\frac{29^2}{32} }}

        t = - 0.0899

Generally the degree of freedom is mathematically represented as

     df =  32+ 32 - 2

     df =  62

The  significance \alpha  is  evaluated as

      \alpha  =  (C - 100 )\%

=>   \alpha  =  (95 - 100 )\%

=>   \alpha  =0.05

The  critical value  is evaluated as

      t_c  =  2  *  t_{0.05 ,  62}

From the student t- distribution table  

        t_{0.05, 62} =  1.67

So

     t_c  =  2 * 1.67

=>  t_c  = 3.34

given that

       t_c  >  t we fail to reject the null hypothesis so  this mean that the result do  not differ

       

6 0
2 years ago
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