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ozzi
2 years ago
9

In ΔGHI, the measure of ∠I=90°, IG = 6.8 feet, and HI = 2.6 feet. Find the measure of ∠G to the nearest degree.

Mathematics
1 answer:
Luda [366]2 years ago
3 0

Answer:

\angle G=20.8\approx 21^{\circ}

Step-by-step explanation:

Given: In ΔGHI, \angle I=90°, IG = 6.8 feet, and HI = 2.6 feet

To find: \angle G

Solution:

Trigonometry defines relationship between the sides and angles of the triangle.

For any angle \theta,

tan\theta = side opposite to \theta/side adjacent to \theta

In ΔGHI,

tan G=\frac{HI}{GI}

Put HI=2.6  \,\,feet\,,\,GI=6.8\,\,feet

So,

tan G=\frac{2.6}{6.8}=0.38

Therefore, \angle G=20.8\approx 21^{\circ}

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<u>ANSWER</u>

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We want to find the cube root of

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The expression under the radical called the radicand.

We need to express this radical in exponential form using the property,

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Applying this rule gives us:

\sqrt[3]{- 729 {a}^{9}  {b}^{6} }  =  ({- 729 {a}^{9}  {b}^{6}})^{ \frac{1}{3} }

\sqrt[3]{- 729{a}^{9}  {b}^{6} }  =  ({- {9}^{3}  {a}^{9}  {b}^{6}})^{ \frac{1}{3} }

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({a}^{m} )^{n} = {a}^{mn}

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