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1 year ago

Evaluate sin(Arcos(-9/√145)).

Mathematics

2 answers:

tino4ka555 [31]1 year ago

8 0

Use the fact that $\sin x = \sqrt{1-\cos^2 x}$ to solve it.

$\sin(\arccos(-\frac{9}{\sqrt{145}}))=\sqrt{1-\cos^2(\arccos(-\frac{9}{\sqrt{145}}))} =\\= \sqrt{1-(-\frac{9}{\sqrt{145}})^2}=\frac{8}{\sqrt{145}}$

makkiz [27]1 year ago

7 0

Answer:

Step-by-step explanation:

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OverLord2011 [107]

Answer with explanation:

Price of Product on the Website = $ 412.50

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Is 9.373 a repeating decimal? Is it rational? Explain your reasoning.

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2 years ago

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Your friend is trying to grow her hair as long as her cousin’s hair. The table shows their hair lengths y (in inches) in differe

Effectus [21]

<span>Given the table that shows the hair lengths y (in inches) of your friend and her cousin in different months x.

Month      Friends Hair(in)      Cousins Hair(in)
    3                     4                              7
    8                    6.5                            9.

To solve for the cousins hair, recall that the equation of a line is given by

y = mx + c

From the table,

7 = 3m + c . . . (1)
9 = 8m + c . . . (2)

(1) - (2) ⇒ -2 = -5m
$\Rightarrow m= \frac{2}{5} =0.4$

Substituting for m into equation (1) gives:

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</span>

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1 year ago

In a recent questionnaire about food, a random sample of 970 adults were asked about whether they prefer eating fruits or vegeta

alukav5142 [94]

Answer:

$Z_{0.05}=1.645$

Step-by-step explanation:

Given :In a recent questionnaire about food, a random sample of 970 adults were asked about whether they prefer eating fruits or vegetables, and 458 reported that they preferred eating vegetables.

To Find :What value of z should be used to calculate a confidence interval with a 95 % confidence level?

Solution:

Confidence level = 95 % i.e.0.95

So, significance level = 5% i.e. 0.05

So, the value of z corresponding to significance level 0.05 should be used to calculate a confidence interval with a 95 % confidence level

So, $Z_{0.05}=1.645$

Hence z should be 1.645 to calculate a confidence interval with a 95 % confidence level.

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1 year ago

To get the best deal on a microwave oven, Jeremy called six appliance stores and asked the cost of a specific model. The prices

White raven [17]

Answer:

Step-by-step explanation:

The prices he was quoted are listed below: $663, $273, $410, $622, $174, $374

We would first determine the mean.

Mean = sum of terms in the data/ number of terms in the data.

Sum of terms =

663 + 273 + 410 + 622 + 174 + 374

= 2516

Number of terms = 6

Mean = 2516/6 = 419.33

Standard deviation = √summation(x - m)^2/n

summation(x - m)^2/n = (663 - 429.33)^2 + (273 - 419.33)^2 + (410 - 419.33)^2 + (622 - 419.33)^2 + (174 - 419.33)^2 + (374 - 419.33)^2

= 179417.9334/6 = 29902.9889

Standard deviation = √29902.9889

= 172.9

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2 years ago