Evaluate sin(Arcos(-9/√145)).

Mathematics

2 answers:

tino4ka555 [31]2 years ago

8 0

Use the fact that $\sin x = \sqrt{1-\cos^2 x}$ to solve it.

$\sin(\arccos(-\frac{9}{\sqrt{145}}))=\sqrt{1-\cos^2(\arccos(-\frac{9}{\sqrt{145}}))} =\\= \sqrt{1-(-\frac{9}{\sqrt{145}})^2}=\frac{8}{\sqrt{145}}$

makkiz [27]2 years ago

7 0

Answer:

Step-by-step explanation:

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A quadratic function has a line of symmetry at x = –3.5 and a zero at –9.

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