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ololo11 [35]
2 years ago
11

To get the best deal on a microwave oven, Jeremy called six appliance stores and asked the cost of a specific model. The prices

he was quoted are listed below: $663, $273, $410, $622, $174, $374 Find the standard deviation for the given data.
Mathematics
1 answer:
White raven [17]2 years ago
6 0

Answer:

Step-by-step explanation:

The prices he was quoted are listed below: $663, $273, $410, $622, $174, $374

We would first determine the mean.

Mean = sum of terms in the data/ number of terms in the data.

Sum of terms =

663 + 273 + 410 + 622 + 174 + 374

= 2516

Number of terms = 6

Mean = 2516/6 = 419.33

Standard deviation = √summation(x - m)^2/n

summation(x - m)^2/n = (663 - 429.33)^2 + (273 - 419.33)^2 + (410 - 419.33)^2 + (622 - 419.33)^2 + (174 - 419.33)^2 + (374 - 419.33)^2

= 179417.9334/6 = 29902.9889

Standard deviation = √29902.9889

= 172.9

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The diagram shows a logo made from three circles
ratelena [41]

Answer:

Use the formula π*(r^2) where r is radius

Area of big circle, all 3=314.1592654 (approximately) and this is =100%

Area of middle circle=153.93804

Area of small circle=78.53981634

Percentage of middle circle with small circle = (153.93804/314.1592654)*100= 48.999999999999 approx= 49%

Percentage of small circle alone = (78.53981634/314.1592654)*100

= 25%

So 51%= big circle alone

And 51%+25%= 76%

100%-76%=24%

3 0
2 years ago
Read 2 more answers
What is the value of k in the equation below? 5k - 2k = 12? 1 1/5, 1 5/7, 3, 4
valkas [14]
Hi there!

5k - 2k = 12
Solve for K
3k = 12
Divide both sides by 3
3k/3 = 12/3
k = 4
The correct answer is : 4


I hope that helps!
Brainliest answer :)
8 0
1 year ago
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Which of the following are terms in the sum of the given polynomials? 3x2,-2x2y, 2xy2, 4y2, xy2, -y2,2x2y
vampirchik [111]
Create the sum of the given polynomial terms.
f(x,y) = 3x² - 2x²y + 2xy² + 4y² + xy² - y² + 2x²y
        = 3x² + 3xy² + 3y²

Test the given terms to see if they belong in f(x,y).
3:       NO
3x²:   YES
3y²:   YES
3xy²: YES
4x²:   NO

Answer:
The terms in the sum of the given polynomials are 3x², 3y², and 3xy².

6 0
2 years ago
From past experience, a company has found that in carton of transistors: 92% contain no defective transistors 3% contain one def
jasenka [17]

Answer:

E(X) = 0*0.92 + 1*0.03 +2*0.03 +3*0.02 = 0.1500

In order to find the variance we need to find first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) = 0^2*0.92 + 1^2*0.03 +2^2*0.03 +3^2*0.02 = 0.3300

The variance is calculated with this formula:

Var(X) = E(X^2) -[E(X)]^2 = 0.33 -(0.15)^2 = 0.3075

And the standard deviation is just the square root of the variance and we got:

Sd(X) = \sqrt{0.3075}= 0.5545

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).  

Solution to the problem

LEt X the random variable who represent the number of defective transistors. For this case we have the following probability distribution for X

X         0           1           2         3

P(X)    0.92     0.03    0.03     0.02

We can calculate the expected value with the following formula:

E(X) = \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) = 0*0.92 + 1*0.03 +2*0.03 +3*0.02 = 0.1500

In order to find the variance we need to find first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) = 0^2*0.92 + 1^2*0.03 +2^2*0.03 +3^2*0.02 = 0.3300

The variance is calculated with this formula:

Var(X) = E(X^2) -[E(X)]^2 = 0.33 -(0.15)^2 = 0.3075

And the standard deviation is just the square root of the variance and we got:

Sd(X) = \sqrt{0.3075}= 0.5545

8 0
2 years ago
Jim Moore opened a new savings account. He deposited $12,000 at 12 percent compounded semiannually. At the start of the fourth y
Andrew [12]

It is 12000 x (1.06)^12 + 50000 x (1.06)^6 = 95,072.31 


start of 4th year to end of 6th year = 6 semi-annual periods where interest is compounded for the second deposit

6 0
1 year ago
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