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1 year ago

The complement of 25% is 52% true or false

Mathematics

2 answers:

ki77a [65]1 year ago

8 0

Answer:

False

Step-by-step explanation:

Complementary Percentages gives 100% after adding, where 100% represents the Grand Total amount.

Let x be the complement percentage of 25 %,

Thus, by the above statement,

x + 25 % = 100 %

x = 100 % - 25 % = 75 %

So, the complement of 25 % is 75 %,

Hence, this is a false statement that the complement of 25% is 52% .

Anettt [7]1 year ago

3 0

False; it would be 75%.

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Step-by-step explanation:

<h3>Given</h3>

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<h3>Solution</h3>

<u>Equations as per given are:</u>

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Step-by-step explanation:

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Read 2 more answers

Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant

pychu [463]

Answer:

A=152

K= -Ln(0.5)/14

Step-by-step explanation:

You can obtain two equations with the given information:

T(14 minutes) = 114◦C

T(28 minutes)=152◦C

Therefore, you have to replace t=14, T=114 and t=28, T=152 in the given equation:

$114=190-Ae^{-14k} (I) \\152=190-Ae^{-28k}(II)$

Applying the following property of exponentials numbers in (II):

$e^{a}.e^{b}=e^{a+b}$

Therefore $e^{-28k}$ can be written as $e^{-14k}.e^{-14k}$

$152=190-Ae^{-14k}.e^{14k}$

Replacing (I) in the previous equation:

$152=190-76e^{-14k}$

Solving for k:

Subtracting 190 both sides, dividing by -76:

$0.5=e^{-14k}$

Applying the base e logarithm both sides:

Ln(0.5)= -14k

Dividing by -14:

k= -Ln(0.5)/14

Replacing k in (I) and solving for A:

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Dividing by 0.5

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