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zhenek [66]
2 years ago
15

heather is training for a long-distance run. her data points listed below represent the days of practice, x, and the number of m

iles run, y.(1, 2.5), (2, 4.2), (4, 5.6), (6, 7), (8, 8.1), (10, 11)use the equation to interpolate the value and estimate the distance that she could have run on day 3. round to the nearest tenth of a mile.
Mathematics
2 answers:
MAXImum [283]2 years ago
3 0
Interpolation equation
Poit 1: (a,b)
Point 2: (c,d)
Intermediate point (x,y)

(d - b)/(c - a) = (y - b) / (x - a)

(a,b) = (2, 4.2)
(c,d) = (4, 5.6)

x = 3

(5.6 - 4.2) / (4 - 2)  =  (y - 4.2) / (3 -2)

y =  [1.4/2]*[1] + 4.2

y = 0.7 + 4.2 = 4.9

Answer 4.9 miles

 




Airida [17]2 years ago
3 0

Answer:

4.6

Step-by-step explanation:

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I think the answer is b but I am not for sure
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What are the classifications of each system? Drag the answer into the box to match each system. {4x−2y=102x−y=5 {y=2x−3−2x+y=−5
siniylev [52]
The first one is. coincident 
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22. What is the percent of increase for a population<br> that changed from 438,000 to 561,000?
ra1l [238]

Answer: 28.08%

Step-by-step explanation: To find the percent increase, we divide the amount of change by the original number.

The amount of change is the difference between the two numbers which in this case is 561,000 - 438,000 and the original number is 438,000.

561,000 - 438,000 is 123,000 so we are left with 123,000 divided by 438,000 which is 0<em>.</em>2808. Finally, since our problem is asking us for a percent, we write 0<em>.</em>2808 as a percent by moving the decimal point two places to the right to get 28.08%.

So when the population changes from 438,000 to 561,000, it has increased by 28.08%.

5 0
2 years ago
A sample of an unknown chemical element naturally loses its mass over time. The relationship between the elapsed time ttt, in mo
Naddik [55]

Answer:

Step-by-step explanation:

Given a sample M(t)

M(t) = 120 • ( 81 / 625)^t

When is the fraction of the mass decay to 3/5 of it's mass

Generally

M(t) = Mo•(k^t)

The original mass is 120

Mo = 120

So, we want to find time when it decay to 3/5 of it's original mas

M = 3/5 × 120

M = 72

Then,

M(t) = 120 • ( 81 / 625)^t

72 = 120 • ( 81 / 625)^t

72 / 120 = ( 81 / 625)^t

0.6 = ( 81 / 625)^t

Take natural logarithmic of both sides

In(0.6) = In(81/625)^t

In(0.6) = t•In(81/625)

t = In(0.6) / In(81/625)

t = In(0.6) / In(0.1296)

t = 0.25 monthly

t = ¼ monthly

6 0
2 years ago
Subtract (7.8 - 5.1t) from (2.8 - 3.2t). Use
tankabanditka [31]

Answer: we can use the commutative property to show the difference in the following ways:-

a. (-3.2t + 2.8) - (-5.1t + 7.8)

b. 1.9t - 5

c. (-3.2t + 2.8) - (-5.1t + 7.8)

Step-by-step explanation:

Commutative simply has to do with "moving around". In the case of addition, the commutative property rule is "x + y = y + x". When it comes to numbers, it my 7 + 8 = 8 + 7. In the case of multiplication, the commutative property rule is "m × n = n × m". So whenever commutative property is referred to, what is expected is "to move around". Commutative property rule can be executed as you pair, add or subtract like terms e.g 2a - 4 + 9a can be rewritten as 2a + 9a - 4 or 11a - 4

In the question, we were asked to subtract (7.8 - 5.1t) from (2.8 - 3.2t) and use the commutative property to show the difference in another way.

Subtracting (7.8 - 5.1t) from (2.8 - 3.2t) will give:-

(2.8 - 3.2t) - (7.8 - 5.1t) (This is the original expression)

Removing the bracket:

2.8 - 3.2t - 7.8 + 5.1t

= 5.1t - 3.2t + 2.8 - 7.8 (we have now shown the difference in another way)

Subtracting the like terms, will give: 1.9t - 5 (This is also the difference shown in another way).

Recall that the initial expression was

(2.8 - 3.2t) - (7.8 - 5.1t).

We can also use the commutative property rule to show the difference in the following way:-

(-3.2t + 2.8) - (-5.1t + 7.8)

By so doing, the figures have been rearranged without altering or affecting the outcome of the expression.

4 0
2 years ago
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