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2 years ago

Which table represents a linear function? A, B, C, D

Mathematics

2 answers:

liq [111]2 years ago

5 0

Answer:

Table B represents a linear function.

Step-by-step explanation:

Table B is a linear function because y goes up by a constant, steady rate of 4 every time x goes up by one.

garik1379 [7]2 years ago

3 0

The table that represents a linear function is B

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Without drawing the graph of the function y=1.2x−7, see if the graph passes through points (-10, 5)

ad-work [718]

Step-by-step explanation:

Substitute x with -10 and y with 5.

(5) = 1.2(10) - 7

5 = 12 - 7

This is obviously true, so the graph indeed passes through the point (-10, 5).

7 0

2 years ago

Determine the points of intersection of the given functions. y = –x2 + 3x + 20 y = –2x + 15 Describe the features of the graphin

Tanzania [10]

After you type in your equations and hit graph you notice that, if you are in the standard window, your parabola is cut off so you have to choose your "window" button to change the viewing window to see the whole graph. Then you would use your 2nd button and "trace" and "intersect" to find the points of intersection of the 2 graphs. The first point is at (-.90901, 16.81812) and the second point is at (5.9090909, 3.1818182). Graphing calculators are quite amazing!

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2 years ago

Read 2 more answers

Cameron, Arthur, and Jamie are playing soccer. Their locations are recorded by a motion tracking system. The grid shows distanc

Luden [163]

Answer:

1. Arthur is about 54 meters away from Cameron.

2. Jamie is about 56 meters away from Cameron.

3. Arthur is closer to Cameron.

Step-by-step explanation:

We have been given the locations of Cameron (70,10), Arthur (20,30) and Jamie (45,60) on the the grid in meters.

1. To find the distances of Arthur and Jamie from Cameron we will use distance formula.

$\text{Distance}=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

$\text{Distance between Cameron and Arthur}=\sqrt{(70-20)^{2}+(10-30)^{2}}$

$\text{Distance between Cameron and Arthur}=\sqrt{(50)^{2}+(-20)^{2}}$

$\text{Distance between Cameron and Arthur}=\sqrt{2500+400}$

$\text{Distance between Cameron and Arthur}=\sqrt{2900}$

$\text{Distance between Cameron and Arthur}=53.8516480713450403\approx 54$

Therefore, the distance Arthur is about 54 meters away from Cameron.

2. Let us find the distance between Cameron and Jamie.

$\text{Distance between Cameron and Jamie}=\sqrt{(70-45)^{2}+(10-60)^{2}}$

$\text{Distance between Cameron and Jamie}=\sqrt{(25)^{2}+(-50)^{2}}$

$\text{Distance between Cameron and Jamie}=\sqrt{625+2500}$

$\text{Distance between Cameron and Jamie}=\sqrt{3125}$

$\text{Distance between Cameron and Jamie}=55.9016994374947424\approx 56$

Therefore, Jamie is about 56 meters away from Cameron.

3. We can see that 56 is greater than 54, therefore, Arthur is closer to Cameron.

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2 years ago

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Using the following prices, calculate the unit price to determine how much it would cost for 7 granola bars and 9 bottles of wat

Alex73 [517]

$7.14 divided by 6 equals $1.19. That means the granola bars cost $1.19, so 7 granola bars would be $8.05. We then bring $8.05 down.

$8.05

$8.72 divided by 8 equals $1.09. That means 1 bottle of water cost $1.09, so 9 bottles of water would be $10.09.

$8.05 + $ 10.09 = $18.14

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1 year ago

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If you withdraw part of your money from a certificate of deposit before the date of maturity, you must pay an interest penalty.

s344n2d4d5 [400]

Answer:

$\frac{3}{12} *100=25\\$

8,3*0,25=2,10%(2d.p)

Step-by-step explanation:

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2 years ago