Question

What is the following product? RootIndex 3 StartRoot 16 x Superscript 7 Baseline EndRoot times RootIndex 3 StartRoot 12 x Superscript 9 Baseline EndRoot

Answer 1

Answer:

$4x^5\sqrt[3]{3x}$

Step-by-step explanation:

I'm not sure I understand the problem, but I think it's this:

$\sqrt[3]{16x^7} \times \sqrt[3]{12x^9} =$

$= \sqrt[3]{16 \times 12 \times x^{16}}$

$= \sqrt[3]{192 \times x^{15} \times x}$

$= \sqrt[3]{64 \times 3 \times (x^5)^3 \times x}$

$= \sqrt[3]{4^3 \times 3 \times (x^5)^3 \times x}$

$= 4x^5\sqrt[3]{3x}$