Question

Martin chose two of the cards below. When he found the quotient of the numbers, his answer was -16/9. Write the division problem that Martin solved

Answer 1

Answer:

The required division problem he must solve is:

$\frac{2}{3} \div \frac{-3}{8} =\frac{2}{3}\times\frac{-8}{3}=\frac{-16}{9}$

Step-by-step explanation:

Consider the provided information.

Martin chose two of the cards below. When he found the quotient of the numbers, his answer was -16/9.

As we know that the quotient of the number is a negative number.

Therefore, the sign of both numbers must be different,

Thus we can concluded he must select $\frac{2}{3}$ as one of the card, so that product is a negative number.

Let the selected card be x.

$\frac{2}{3} \div x =\frac{-16}{9}\\\\x=\frac{2}{3}\div\frac{-16}{9}\\\\x=\frac{2}{3}\times\frac{-9}{16}\\\\x=\frac{-3}{8}$

Hence, the two cards should be $\frac{2}{3}$ and $\frac{-3}{8}$

The required division problem he must solve is:

$\frac{2}{3} \div \frac{-3}{8} =\frac{2}{3}\times\frac{-8}{3}=\frac{-16}{9}$