Answer:
(a). 72.9%.
(b). 13.6 hr.
Step-by-step explanation:
So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;
=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "
=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"
So, we will be making use of the Crawford learning curve model.
T(7) + 10 = T (17) = 30 min.
T(7) = T1(7)^b = 45.
T(17 ) = T1(17)^b = 30.
(T1) = 45/7^b = 30/17^b.
45/30 = 7^b/17^b = (7/17)^b.
1.5 = (0.41177)^b.
ln 1.5 = b ln 0.41177.
0.40547 = -0.8873 b.
b = - 0.45696.
=> 2^ -0.45696 = 0.7285.
= 72.9%.
(b). T1= 45/7^ - 045696 = 109.5 hr.
V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .
V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .
= 815.7 min .
= 13.595 hr.
80% of 90 may be found by multiply 90 by 0.8. Once you have that number, you can use it to set up a proportion with 2/5 (the simplified form of 40/100). Thus, you will write out 72/x = 2/5, since x is the number that you're solving for. Multiply numerators and denominators of opposite fractions to get the equation 72(5) = 2x. Finally, simplify 360 = 2x by dividing both sides by 2 to isolate the variable. You should have your answer by now.
Answer:
The y-intercept is 3000. The slope is -275. Therefore, your equation in slope intercept form is y = -275x +3000.
Step-by-step explanation:
Y intercept is found where x = 0 or on the y axis, so the only place on this graph where x = 0 and there is a number on the y axis is at (0, 3000), making 3000 your y intercept. The slope is figured from two points, and taking y2-y1/x2-x1. This would give you 3000-2450/2-0 which is -550/2 which is -275. That's your slope. Slope intercept form is y = mx+b, where m is the slope and b is the y intercept. Just plug in, and you get y = -275x+3000
Answer:
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Step-by-step explanation:
Answer:
b. strong; negative
Step-by-step explanation:
When a correlation has a value greater than 0.74 or lesser than -0.70, it is classified as a strong correlation.
A negative value for a correlation means a negative (downhill) linear correlation.
Therefore, since the correlation coefficient found by Frank Fitness is -0.74, there is a strong and negative relationship between hours of strenuous exercise and body mass.
