The ratio here would be 4 to 18, in which 4 represents the number of
black covers sold and 18 represents the total of covers sold.
43.586
nearest 10th= 43.6
nearest 100th= 43.59
nearest 1 =44<span />
We can create a parabola equation of the trajectory using
the vertex form:
y = a (x – h)^2 + k
The center is at h and k, where h and k are the points at
the maximum height so:
h = 250
k = 120
Therefore:
y = a (x – 250)^2
+ 120
At the initial point, x = 0, y = 0, so we can solve for
a:
0 = a (0 – 250)^2 + 120
0 = a (62,500) + 120
a = -0.00192
So the whole equation is:
y = -0.00192 (x – 250)^2 + 120
So find for y when the golf ball is above the tree, x =
400:
y = -0.00192 (400 - 250)^2 + 120
y = 76.8 ft
So the ball cleared the tree by:
76.8 ft – 60 ft = 16.8 ft
Answer:
16.8 ft
Parker family drove 120 miles on the first day
Step-by-step explanation:
Given:
Total miles driven on the road trip= 180 miles
solution:
Lets assume the distance drove on the first day is x
The total distance covered on the road trip is 180 miles. so,


Hence, x = 120.
The distance travelled on the first day is 120 miles.
Answer:
A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:
A. closed at both ends
B. open at one end and closed at one end
C. open at both ends.
D. we cannot tell because we do not know the frequency of the sound.
The right choice is:
B. open at one end and closed at one end
.
Step-by-step explanation:
Given:
Length of the pipe,
= 120 cm
Its wavelength
= 480 cm
= 160 cm and
= 96 cm
We have to find whether the pipe is open,closed or open-closed or none.
Note:
- The fundamental wavelength of a pipe which is open at both ends is 2L.
- The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.
So,
The fundamental wavelength:
⇒ 
It seems that the pipe is open at one end and closed at one end.
Now lets check with the subsequent wavelengths.
For one side open and one side closed pipe:
An odd-integer number of quarter wavelength have to fit into the tube of length L.
⇒
⇒ 
⇒
⇒ 
⇒
⇒ 
⇒
⇒
So the pipe is open at one end and closed at one end
.