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fenix001 [56]
2 years ago
8

A local arts council has 200 members. The council president wanted to estimate the percent of its members who have had experienc

e in writing grants. The president randomly selected 30 members and surveyed the selected members on their grant-writing experience. Of the 30 selected members, 12 indicated that they did have the experience. Have the conditions for inference with a one-sample z -interval been met
Mathematics
1 answer:
garri49 [273]2 years ago
6 0

Answer:

Yes the sample can be use to make inference

Step-by-step explanation:

The inference is possible if the conditions:

p*n > 10      and   q*n > 10

where p and q are the proportion probability of success and q = 1 - p

n is sample size

Then   p = 12 / 30  = 0,4         q =  1 - 0,4    q  =  0,6

And  p*n  =  0,4 * 30  = 12            12 > 10

And  q*n  = 0,6 * 30   = 18            18 > 10

Therefore with that sample the conditions to approximate the binomial distribution to a Normal distribution are met

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A shop sells chocolate, vanilla and strawberry ice creams. 45% of the ice creams sold are vanilla, and 1/4 are strawberry. What
labwork [276]

Answer:

30% of ice cream are chocolate

Step-by-step explanation:

45% = vanilla

1/4 = strawberry

(1/4)×100 = 25%

chocolate = 100%-45%-25%

= 30%

8 0
2 years ago
Read 2 more answers
Ne Friday night, a group of friends bought 5 containers of popcorn and 4 granola bars at the movie theatre for $42.50. The next
Tomtit [17]

In this question , it is given that p represents cost of 1 container of popcorn . Therefore cost of 5 containers of popcorn = 5p and cost of 3 containers of popcorn = 3p .

And g represents cost of 1 container of granola bars. THerefore cost of 4 containers of granola bars = 4g and cost of 6 containers of granola bars = 6g .

According to the given question, the required linear equations are

5p+4g=42.50 , 3p+6g =34.50 .

And these are the the required system of linear equation .

4 0
2 years ago
What are the domain and range of f (x) = (one-fifth) Superscript x?
natka813 [3]

Answer:

The domain of the function is all real numbers (-\infty,\infty) and the range is all positive real numbers (0,\infty)

Step-by-step explanation:

We have the following function f(x)=(\frac{1}{5} )^x and we want to find the domain and the range.

The function we have is an example of an exponential function f(x)=b^x with b > 0 and b ≠ 1. This types of functions in general have the following properties:

  • It is always greater than 0, and never crosses the x-axis
  • Its domain is the set of real numbers
  • Its Range is the Positive Real Numbers (0,\infty)

The domain of a function is the specific set of values that the independent variable in a function can take on.

When determining domain it is more convenient to determine where the function would not exist.

This function has no undefined points nor domain constraints. Therefore the domain is (-\infty,\infty).

The range is the resulting values that the dependent variable can have as x varies throughout the domain. Therefore the range is (0,\infty).

We can check our results with the graph of the function.

7 0
2 years ago
Read 2 more answers
A scientist mixes x liters of water into a container that has 10 liters of a mixture that is 12% salt and 88% water. The functio
dsp73

Answer:

110 liters of water

Step-by-step explanation:

Let

x ----> liters of water

f(x) ---->  the percent of the sat in the new mixture

we have

f(x)=\frac{1.2}{x+10}

For f(x)=1\%=1/100=0.01

substitute in the equation

0.01=\frac{1.2}{x+10}

solve for x

x+10=\frac{1.2}{0.01}

x+10=120\\x=120-10\\x=110\ L

5 0
2 years ago
Suppose that the weight of navel oranges is normally distributed with a mean µµ = 8 ounces, and a standard deviation σσ = 1.5 ou
monitta

Answer:

Hello some parts of your question is missing below is the missing part

c. If you randomly select a navel orange, what is the probability that it weighs between6.2 and 7 ounces

Answer: A) 0.0099

              B) 0.6796

              C) 0.13956

Step-by-step explanation:

weight of Navel oranges evenly distributed

mean ( u ) = 8 ounces

std ( б )= 1.5

navel oranges = X

A ) percentage of oranges weighing more than 11.5 ounces

P( x > 11.5 ) = P ( \frac{x - u}{ std} > \frac{11.5-8}{1.5} )

                   = P ( Z > 2.33 ) = 0.0099

                   = 0.9%

B) percentage of oranges weighing less than 8.7 ounces

  P( x < 8.7 ) = P ( \frac{x - u}{ std} > \frac{8.7-8}{1.5} )

                    = P ( Z < 0.4667 ) = 0.6796

                    = 67.96%

C ) probability of orange selected weighing between 6.2 and 7 ounces?

P ( 6.2 < X < 7 ) = P (\frac{6.2-8}{1.5} <  \frac{x - u}{ std} < \frac{7-8}{1.5} )

                          = P ( -1.2 < Z < -0.66 )

                          = Ф ( -0.66 ) - Ф(-1.2) = 0.13956

7 0
2 years ago
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