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2 years ago

Suppose the supply function for product x is given by qxs = - 30 + 2px - 4pz.

Mathematics

1 answer:

Igoryamba2 years ago

3 0

It is given in the question that

Suppose the supply function for product x is given by

$qxs = - 30 + 2px - 4pz.$

And we have to find how much of product x is produced when px = $600 and pz = $60.

And for that, we have to substitute 600 for px and 60 for pz, and on doing so, we will get

$qxs = -30+2(600)-4(60)
\\
qxs = -30 +1200 -240 = 930$

And that's the required answer .

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HELP 64 POINTS

kodGreya [7K]

Answer: {30, 39, 33, 15, 15, 18, 20, 33, 19, 41, 45, 18}

Step-by-step explanation:

1. The key indicates you how to read the values of the stem-and-leaf plot. Then, 1|5 means 15.

2. Then, the first digit is written in the colum Stem and the second digit in the column Leaf.

3. Based on this information, you can write the data given in the stem-and-leaf plot, as following:

15, 15, 18, 18, 19 (The first digit is 1 and the second digit are: 5,5,8,8 and 9)

20 (The first digit is 2 and the second digit is 0)

30, 33, 33, 39 (The first digit is 3 and the second digit are: 0,3,3 and 9)

41, 45 (The first digit is 4 and the second digit are: 1 and 5)

3. Then, as you can see, the data set represented by the stem-and-leaf plot is:

{30, 39, 33, 15, 15, 18, 20, 33, 19, 41, 45, 18}

5 0

2 years ago

Read 2 more answers

The archway of the main entrance of a university is modeled by the quadratic equation y = -x^2 + 6x. The university is hanging a

Galina-37 [17]

So the problem ask on which of the following choices you had is the points should the banner be attached in the archway and the best answer among the choices will be letter C. (1.5, 4.87) and (3.5, 4.37). I hope this will help you and feel free to ask for more.

8 0

3 years ago

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What is the domain of validity for csctheta =start fraction 1 over sine theta end fraction? (1 point) all real numbers all real

dem82 [27]

We know the following relationship:

$csc(\theta)=\frac{1}{sin(\theta)}$

The domain of a function are the inputs of the function, that is, a function $f$ is a relation that assigns to each element $x$ in the set A exactly one element in the set B. The set A is the domain (or set of inputs) of the function and the set B contains the range (or set of outputs).Then applying this concept to our function $csc(\theta)$ we can write its domain as follows:

1. Domain of validity for $csc(\theta)$ :

$D: \{\theta \in R/ sin(\theta) \neq 0 \} \\ In words: All \ \theta \ that \ are \ real \ values \ except \ those \ that \ makes \ sin(\theta)=0$

When:

$sin(\theta)=0$ ?

when:

$\theta=..., -2\pi,-\pi,0,\pi,\2pi,3pi,...,k\pi$

where k is an integer either positive or negative. That is:

$sin(k\theta)=0 \ for \ k=...,-2,-1,0,1,2,3,...$

To match this with the choices above, the answer is:

"All real numbers except multiples of $\pi$ "


2. which identity is not used in the proof of the identity $1+cot^{2}(\theta)=csc^{2}(\theta)$ :

This identity can proved as follows:

$sin^2{\theta}+cos^{2}(\theta)=1 \ Dividing \ by \ sin^{2}(\theta) \\ \\ \therefore \frac{sin^2{\theta}}{sin^{2}(\theta)}+\frac{cos^{2}(\theta)}{sin^{2}(\theta)}=\frac{1}{sin^{2}(\theta)} \\ \\ \therefore 1+cot^{2}(\theta)=csc^{2}(\theta)$

The identity that is not used is as established in the statement above:

"1 +cos squared theta over sin squared theta= csc2theta"

Written in mathematical language as follows:

 $\frac{1+cos^{2}(\theta)}{sin^{2}(\theta)}=csc^{2}(\theta)$

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2 years ago

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An epidemiologic survey of roller-skating injuries in Metroville, a city with a population of 100,000 (during the midpoint of th

Ahat [919]

Answer: c. $\dfrac{90}{1800}\times100\%$

Step-by-step explanation:

As per given , we have

Total number of residents injured from roller-skating =1,800

Total number of deaths from roller-skating = 90

Formula for Mortality rate : $Mortaility\ rate= \dfrac{Deaths\ due \ to\ injury}{Tota\ injuries}$

Then, the proportional mortality ratio (%) due to roller-skating was

= $\dfrac{90}{1800}\times100\%$

= 5%

Hence, the correct answer is c. $\dfrac{90}{1800}\times100\%$

8 0

2 years ago

13 If B is the midpoint of AC, and AC = 8x – 20, find BC. 3x-1 А в

Papessa [141]

Answer:

BC = 26

Step-by-step explanation:

Given that:

B is the midpoint of AC

Then AC = AB + BC

AC = 8x - 20 and AB = 3x - 1

Then,

8x - 20 = (3x - 1) + BC

8x - 20 - (3x - 1) = BC

8x - 20 - 3x + 1 = BC

5x - 19 = BC

But AB = BC

5x - 19 = 3x - 1

5x - 3x = - 1 + 19

2x = 18

x = 9

Hence,

Since BC = AB = 3x - 1

3(9) - 1

27 - 1

= 26

7 0

2 years ago