Question

The archway of the main entrance of a university is modeled by the quadratic equation y = -x^2 + 6x. The university is hanging a banner at the main entrance at an angle defined by the equation 4y = 21 − x. At what points should the banner be attached to the archway?
A.) (1, 5.5) and (5.25, 6.56)
B.) (1, 5) and (5.25, 3.94)
C.) (1.5, 4.87) and (3.5, 4.37)
D.) (1.5, 5.62) and (3.5, 6.12)
E.) There is no real solution

Answer 1

So the problem ask on which of the following choices you had is the points should the banner be attached in the archway and the best answer among the choices will be letter C. (1.5, 4.87) and (3.5, 4.37). I hope this will help you and feel free to ask for more.

Answer 2

Answer:

(1, 5) and (5.25, 3.94)

Step-by-step explanation:

The archway of the main entrance of a university is modeled by the quadratic equation : $y = -x^2 + 6x$  

The university is hanging a banner at the main entrance at an angle defined by the equation $4y = 21 - x$

Now we are supposed to find At what points should the banner be attached to the archway.

So, we are supposed to find the intersections points of the two given equations.

Refer the attached figure

$y = -x^2 + 6x$ -- Black line

$4y = 21 - x$ -- Red line

Thus the intersection points of given equations are : (1, 5) and (5.25, 3.94)

Hence the banner be attached at (1, 5) and (5.25, 3.94) to the archway.