For a probability distribution the expected value is the summation of product of probabilities with their respective data values. Let x be the probability that Jackson goes gym for 2 days and y be the probability that he goes gym for 3 days.
For the given case we have following values and their probabilities:
0 : 0.1
2 : x
3 : y
So the expected value will be = 0(0.1) + 2(x) + 3(y)
Expected value is given to be 2.05. So we can write the equation as:
2x + 3y = 2.05 (Equation 1)
Also for a probability distribution, the sum of probabilities must always equal to 1. So we can set up the second equation as:
0.1 + x + y = 1
x + y = 0.9 (Equation 2)
From Equation 2 we can write the value of x to be x = 0.9 - y. Using this value in equation 1, we get:
2(0.9 - y) + 3y = 2.05
1.8 - 2y + 3y = 2.05
1.8 + y = 2.05
y = 0.25
Using the value of y in equation 2 we get value of x to be 0.65
Therefore we can conclude that:
The probability that Jackson goes to gym for 2 days is 0.65 and the probability that he goes to gym for 3 days is 0.25
Answer:
The record holder is 5.58 m.
Step-by-step explanation:
3.7+1.88=5.58
Answer:
$ 24.30
Step-by-step explanation:
1. $32.40 multiplied by 15 which would equal 486
2. Then you would do 486 divided by 20 which would equal $24.3
3. Then you just add the zero the the end
1. You have the following information given in the problem above:
- Ella mixed<span> two kinds of candy the price of which was $2 and $4 per pound.
- Ella got a 10-lb mix of candy, which cost $2.90 per pound.
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2. Therefore, let's call:
x: pounds of the first kind of candy.
y: pounds of the second kind of candy.
3. Then, you have:
2x+4(10-x)=(2.90)(10)
4. When you clear x, you obtain:
2x+40-4x=29
-2x=29-40
x=-11/-2
x=5.5 pounds
x+y=10
y=10-x
y=10-5.5
y=4.5 pounds
